course Mth 163 I|assignment #019
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01:23:14 ** If you have two points you can solve the simultaneous equations. If you have a more extensive data set you use transformations. For exponential data you plot log(y) vs. x. If the graph is a straight line then you have a good fit. If the slope is m and the vertical intercept is b then your graph gives you log(y) = m x + b. You invert the transformation using the inverse function 10^x, obtaining 10^log(y) = 10^(mx+b) so that y = 10^(mx) * 10^b, and then rearrange this into the desired form. Note that if a power function fits the data then log y vs. log x will give a straight line so that log y = m log x + b. In this case our solution will be y = 10^b * x^m, a power function rather than an exponential function. **
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RESPONSE --> If you have two points you can solve the simultaneous equations. If you have a more extensive data set you use transformations. For exponential data you plot log(y) vs. x. If the graph is a straight line then you have a good fit. If the slope is m and the vertical intercept is b then your graph gives you log(y) = m x + b. You invert the transformation using the inverse function 10^x, obtaining 10^log(y) = 10^(mx+b) so that y = 10^(mx) * 10^b, and then rearrange this into the desired form. Note that if a power function fits the data then log y vs. log x will give a straight line so that log y = m log x + b. In this case our solution will be y = 10^b * x^m, a power function rather than an exponential function. self critique assessment: 3
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