Asst 0

course Mth164

Did not quite understand some of the questions, until they were answered

Iöòyö|ç¬åÙ¢Óq´õßßwáü¯úªŸà‘Ëåºassignment #001

001. Radian measure and the unit circle.

Precalculus II

09-07-2008

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00:22:54

We see visually that the point a lies at an arc distance less than the radius of the circle. We also see that the point c lies at an arc distance that is clearly greater than the radius of the circle. The only possible candidate for a 1 radian angle, which must lie at an arc distance equal to one radius, is therefore point b.

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RESPONSE -->

ok

self critique assessment:

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00:36:14

`q002. If the first ant moves at a constant speed, moving through 1 radian every second, then approximately how long, to the nearest second, do you think it will take for the ant to move along the arc to the point where the circle meets the negative x-axis?

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RESPONSE -->

3, because 1 radian is 60 degrees and the ant would have to go 180 degress to get the negative x- axis

confidence assessment: 1

Right idea, but remember that radian is a little less than 60 degrees. 60° is a reasonable approximation to be used for ballpark estimates.

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00:37:37

Visual examination, perhaps accompanied by a quick sketch, shows that it takes approximately 3 arcs each of one radian to get from the positive x-axis to the negative x-axis when moving along the arc of the circle.

In figure 37 the points b, c and d lie at approximately 1, 2 and 3 radians. Remember that each radian corresponds to an arc distance equal to the radius of the circle.

At 1 radian / second it will take about 3 seconds to move the approximately 3 radians to the negative x axis.

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RESPONSE -->

self critique assessment: 3

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00:41:10

`q003. If the ant traveled at 1/2 radian per second, then after 1 second would its angular position be indicated by point a, point b, point c or point d in Figure 37?

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RESPONSE -->

point a, by looking at the figure point b looks to be at about 60 degrees(1 radian), and point a looks to be about half of that.

confidence assessment: 3

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00:41:32

After 1 second the angular position would be 1/2 radian, which would correspond to point a.

Note that after 2 seconds the angular position would be 1 radian, corresponding to point b, and after three seconds the angular position would be 3 * 1/2 radian = 3/2 radian and the ant would be at position c.

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RESPONSE -->

self critique assessment: 3

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00:44:11

`q004. How far will the ant travel in the process of completing 1 trip around the circle, starting and ending at the initial point where the circle meets the positive x-axis.

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RESPONSE -->

6 radians, 1 radian=60 degrees, complete circle is 360 degrees. 360/60=6

confidence assessment: 2

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00:45:33

The circumference of the circle is 2 pi r, where r is the radius of the circle. This is the distance traveled by the ant.

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RESPONSE -->

I didnt quite understand what kind of answer you were wanting with that question.

self critique assessment: 3

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00:46:38

`q005. As we just saw the distance around the circle is its circumference 2 pi r, where r is the radius. Through how many radians would the ant travel from the initial point, where the circle meets the positive x-axis, if the motion was in the counterclockwise direction and ended at the original point after having completed one trip around the circle.

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RESPONSE -->

6 radians, as stated in the last problem

confidence assessment: 3

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00:47:27

An arc displacement of r corresponds to an arc distance of 1 radian on the circle. Arc distances of 2, 3, 4, ... time the radius would correspond to 2, 3, 4, ... radians of arc. That is, arc distance of r, 2r, 3r, 4r, ... correspond to 1, 2, 3, 4, ... radians of arc.

We understand by these examples that if we divide the arc distance by the radius, we will get the number of radians of angular distance.

The arc distance around the circle is 2 pi r, which therefore corresponds to 2 pi r / r = 2 pi radians.

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RESPONSE -->

self critique assessment: 3

6 radians is a good estimate, but 2 pi radians is the correct result here.

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00:56:13

`q006. The unit circle is a circle of radius 1 centered at the origin. What are the coordinates of the points where the unit circle meets the positive x-axis, the positive y axis, the negative x-axis and the negative y axis?

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RESPONSE -->

positive x axis= 2pi. negative x-axis= pi

positive y-axis= pi/2. negative y-axis= 3pi/2

There is 2pi in a circle. The positive y-axis is 1/4 of 2pi, so on and so forth

confidence assessment: 3

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00:56:49

The unit circle has radius 1 and is centered at the origin, so the circle meets the positive x-axis 1 unit from the origin at (x, y) = (1,0). Similarly the circle meets the positive y-axis at the 'top' of the circle, 1 unit from the origin at (x, y) = (0,1); the circle meets the negative x-axis at (-1, 0); and the circle meets the negative y-axis at (0,-1).

Figure 84 shows these points on the unit circle. Note that in this figure the small dots are located at increments of .1 unit in the x and y directions.

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RESPONSE -->

self critique assessment: 3

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20:19:48

`q007. Without looking at Figure 84, sketch a picture of the unit circle, complete with labeled points where the circle meets the x and y axes. Indicate the arc from the standard initial point, where the circle meets the x-axis, to the point where the circle meets the positive y axis. Describe your sketch.

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RESPONSE -->

The circle though the x- axis at -1and 1 , the y axis at -1 and 1. The arc from the standard initial point to the x axis is pi, and to the positive y axis is pi/2.

confidence assessment: 2

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20:22:32

09-07-2008 20:22:32

Your sketch should show the x and y axes and a circle of radius 1, with the points (1,0), (0, 1), (-1, 0) and (0, -1) where the circle meets the coordinate axes labeled. The arc will run along the first quadrant of the circle from (1,0) to (0,1). Your figure should match figure 84.

You should be able to quickly draw this picture any time you need it.

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NOTES -------> I drew the pictue correctly but once again misunderstood what you were wanting with arc. remember coordinates

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20:43:18

`q008. How many radians of angular displacement correspond to the arc displacement from the standard initial point, where the circle meets the x-axis, to the point where the circle meets the positive y axis?

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RESPONSE -->

To the x axis would be pi. to the positive y axis is pi/2.

confidence assessment: 2

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20:46:39

The trip around the entire circle, which corresponds to an angular displacement of 2 pi radians, corresponds to a trip from the initial point to the point where the circle meets the positive y-axis (i.e., the point (0,1)), then from this point to the point where the circle meets the negative x-axis (i.e., the point (-1,0)), then from this point to the point where the circle meets the negative y-axis (i.e., the point (0,-1)), then from this point back to the point where the circle meets the positive x-axis (i.e., the point (1,0)).

Because of the symmetry of the circle, the arc corresponding to each of these displacements is the same. The arc from (1,0) to (0,1) is 1/4 of the 2 pi radian angular displacement around the entire circle, so its angular displacement is 2 pi/4 = pi/2 radians.

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RESPONSE -->

understood the concept, slightly misunderstood the question.

self critique assessment: 3

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20:50:17

`q009. We have just seen that the angular position of the (1,0) point is 0 and the angular position of the (0,1) point is pi/2. What are the angular positions of the (-1,0) and (0,-1) points?

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RESPONSE -->

The angular position of (-1,0) is pi radians. The angular positiion of (0,-1) is 3pi/2 radians

confidence assessment: 3

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20:51:03

These points are reached after successive angular displacements of pi/2. The (-1,0) point is reached from the pi/2 position by an additional angular displacement of pi/2, which puts it at angular position pi.

The (0,-1) point is reached after another angular displacement of pi/2, which puts it at pi + pi/2 = 2 pi/2 + pi/2 = 3 pi/2.

Note that still another angular displacement of pi/2 puts us back at the initial point, whose angular position is 0. This shows that the initial point has angular position 0, or angular position 3 pi/2 + pi/2 = 4 pi/2 = 2 pi, consistent with what we already know.

You should label your picture with these angular positions pi/2, pi, 3 pi/2 and 2 pi specified at the appropriate points.

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RESPONSE -->

self critique assessment: 3

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20:55:40

`q010. What is the angular displacement from the standard initial point of the point halfway along the arc of the circle from (1,0) to (0,1)? Note that you should begin with a sketch of the circle and of the arc specified here.

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RESPONSE -->

The angular displacment would be pi/4 radians, because the arc specified would be pi/2 radians and half of the is pi/4 radians.

confidence assessment: 2

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20:56:00

(1,0) is the point at which the circle meets the positive x-axis and (0,1) is the point at which the circle meets the positive y-axis. The trip along the arc of the circle from (1,0) to (0,1) will move along the first-quadrant arc from angular position 0 to angular position pi/2. Halfway along this arc, the angular position will be 1/2 * pi/2 = pi/4.

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RESPONSE -->

self critique assessment: 3

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21:02:24

`q011. What will be the angular positions of the arc points halfway between the (0,1) and (-1,0) points of the circle?

What will be the angular positions of the arc points halfway between the (-1,0) and (0,-1) points of the circle?

What will be the angular positions of the arc points halfway between the (0,-1) and (1,0) points of the circle?

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RESPONSE -->

Halfway between (0,1) and (-1,0) would be 3pi/4. Halfway between (-1,0) and (0,-1) would be 5pi/4. Halfway between (0,-1) and (1,0) would be 7pi/4

confidence assessment: 2

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21:02:41

Halfway between the (0,1) point, which corresponds to the the the position pi/2, and the (-1,0) point, which corresponds to angular position pi, will be the point lying at angular position pi/2 + pi/4 = 2 pi / 4 + pi / 4 = (2 pi + pi)/4 = 3 pi / 4.

Halfway between the (-1,0) point, which corresponds to the the position pi,and the (0,-1) point, which corresponds to angular position 3 pi / 2, will be the point lying at angular position pi + pi/4 = 4 pi / 4 + pi / 4 = (4 pi + pi)/4 = 5 pi / 4.

Halfway between the (0,-1) point, which corresponds to the the position 3 pi/2, and the (-1,0) point, which corresponds to angular position 2 pi, will be the point lying at angular position 3 pi/2 + pi/4 =62 pi / 4 + pi / 4 = (6 pi + pi)/4 = 7 pi / 4.

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RESPONSE -->

self critique assessment: 3

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21:07:03

`q012. What is the angular position of the point lying 1/3 of the way along the arc of the circle between the points (1,0) and (0,1)?

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RESPONSE -->

pi/6, because all the way to the x axis would be pi, half of that would be pi/2, a third of that would be pi/6

confidence assessment: 3

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21:07:18

The arc from (1,0) to (0,1) corresponds to an angular displacement of pi/2. One-third of the arc corresponds to an angular displacement of 1/3 * pi/2 = pi/6. The angular position of the specified point is therefore pi/6.

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self critique assessment: 3

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21:07:58

Complete Assignment 0: Complete the remainder of Assignment 0 as instructed under the Assts link on the homepage at 164.106.222.236. This includes the links to What to Include in Submitted Work, Precalculus II Week I and the optional DERIVE worksheet (requires approximately 2 hours for an orientation to a computer algebra and graphing system)

When you have completed the entire assignment run the Query program. Submit SEND files from Query and q_a_.

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RESPONSE -->

self critique assessment: 3

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Very good work. You had a few misreadings, but it appears you understand everything.