course Mth 163 assignment #011
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17:03:16 `q001. Note that this assignment has 11 questions How many squares one foot on a side would it take to construct a square two feet on a side?
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RESPONSE --> It would take 2 one-ft. squares to make a 2-foot square confidence assessment: 2
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17:30:20 A common response is that it takes 2 one-ft. squares to make a 2-foot square. However, below thought shows that this isn't the case. If we put 2 one foot squares side by side we get a one-foot by two-foot rectangle, not a square. If we put a second such rectangle together with the first, so that we have 2 rows with 2 squares in a row, then we have a two-foot square. Thus we see that it takes 4 squares one foot on a side to make a square 2 ft. on a side.
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RESPONSE --> Oh. I get it now. I was thinking wow this is an easy question and if i would've thought about it more, I would've come up with the correct answer the first time. self critique assessment: 3
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17:43:53 `q002. How many cubes one foot on a side would it take to construct a cube two feet on a side?
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RESPONSE --> It would take 2 layers, both containing 2 rows with 2 cubes in a row. Each layer now has 4 cubes, so our two layers contain 8 cubes altogether. confidence assessment: 2
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18:00:20 We could begin by constructing two rows with two cubes in a row, which would sit on a square two feet by two feet. However this would not give is a cube two feet on a side, because at this point the figure we have constructed is only one foot high. So we have to add a second layer, consisting of two more rows with two cubes a row. Thus we have 2 layers, each containing 2 rows with 2 cubes in a row. Each layer has 4 cubes, so our two layers contain 8 cubes.
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RESPONSE --> This question was a lot like the other one, but I thought it out and got the correct answer this time. self critique assessment: 3
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18:07:31 `q003. How many squares one foot on a side would it take to construct a square three feet on a side?
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RESPONSE --> We would need three rows, each containing 3 squares, for an altogether total of 9 squares confidence assessment: 3
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18:19:37 We would require three rows, each with 3 squares, for a total of 9 squares.
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RESPONSE --> Got it! self critique assessment: 3
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18:25:51 `q004. How many cubes one foot on a side would take to construct a cube three feet on a side?
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RESPONSE --> It would take three layers to make a cube three feet high. Each layer would have to contain 3 rows each with three cubes. Each layer would contain 9 cubes, so altogether the three-layer structure would contain 27 cubes confidence assessment: 3
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18:33:19 This would require three layers to make a cube three feet high. Each layer would have to contain 3 rows each with three cubes. Each layer would contain 9 cubes, so the three-layer construction would contain 27 cubes.
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RESPONSE --> I was confident about this. I just have to make sure I think about it and draw a picture. self critique assessment: 3
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18:49:21 `q005. Suppose one of the Egyptian pyramids had been constructed of cubical stones. Suppose also that this pyramid had a weight of 100 million tons. If a larger pyramid was built as an exact replica, using cubical stones made of the same material but having twice the dimensions of those used in the original pyramid, then what would be the weight of the larger pyramid?
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RESPONSE --> The weight of the pyramid would be 800 million tons confidence assessment: 2
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18:55:54 Each stone of the larger pyramid has double the dimensions of each stone of the smaller pyramid. Since it takes 8 smaller cubes to construct a cube with twice the dimensions, each stone of the larger pyramid is equivalent to eight stones of the smaller. Thus the larger pyramid has 8 times the weight of the smaller. Its weight is therefore 8 * 100 million tons = 800 million tons.
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RESPONSE --> I wasn't positive about this. It's nice to see the steps typed out, so I can look over the steps I took and make sure I did everything correctly. self critique assessment: 3
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19:03:14 `q006. Suppose that we wished to paint the outsides of the two pyramids described in the preceding problem. How many times as much paint would it take to paint the larger pyramid?
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RESPONSE --> There would be 4 times the area to paint. The pyramid would take 4 times as much to paint. confidence assessment:
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19:12:18 `q006. Suppose that we wished to paint the outsides of the two pyramids described in the preceding problem. How many times as much paint would it take to paint the larger pyramid?
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RESPONSE --> confidence assessment: 2
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19:40:39 The outside of each pyramid consists of square faces of uniform cubes. Since the cubes of the second pyramid have twice the dimension of the first, their square faces have 4 times the area of the cubes that make up the first. There is therefore 4 times the area to paint, and the second cube would require 4 times the paint
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RESPONSE --> Okay. I got this one. self critique assessment: 3
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19:51:01 `q007. Suppose that we know that y = k x^2 and that y = 12 when x = 2. What is the value of k?
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RESPONSE --> k = 3 confidence assessment: 3
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19:59:10 To find the value of k we substitute y = 12 and x = 2 into the form y = k x^2. We obtain 12 = k * 2^2, which we simplify to give us 12 = 4 * k. The dividing both sides by 410 reversing the sides we easily obtain k = 3.
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RESPONSE --> Got it. self critique assessment: 3
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20:04:38 `q008. Substitute the value of k you obtained in the last problem into the form y = k x^2. What equation do you get relating x and y?
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RESPONSE --> y = 3 x^2 confidence assessment: 3
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20:13:53 We obtained k = 3. Substituting this into the form y = k x^2 we have the equation y = 3 x^2.
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RESPONSE --> Answered this one correctly. self critique assessment: 3
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20:22:34 `q009. Using the equation y = 3 x^2, determine the value of y if it is known that x = 5.
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RESPONSE --> y = 3 (5)^2 = 3 * 25 = 75 confidence assessment: 3
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20:37:40 If x = 5, then the equation y = 3 x^2 give us y = 3 (5)^2 = 3 * 25 = 75.
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RESPONSE --> Got it self critique assessment: 3
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20:49:24 `q010. If it is known that y = k x^3 and that when x = 4, y = 256, then what value of y will correspond to x = 9? To determine your answer, first determine the value of k and substitute this value into y = k x^3 to obtain an equation for y in terms of x. Then substitute the new value of x.
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RESPONSE --> Final Solution: y = 4 * 9^3 = 4 * 729 = 2916 confidence assessment: 3
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20:55:54 To we first substitute x = 4, y = 256 into the form y = k x^3. We obtain the equation 256 = k * 4^3, or 256 = 64 k. Dividing both sides by 64 we obtain k = 256 / 64 = 4. Substituting k = 4 into the form y = k x^3, we obtain the equation y = 4 x^3. We wish to find the value of y when x = 9. We easily do so by substituting x equal space 9 into our new equation. Our result is y = 4 * 9^3 = 4 * 729 = 2916.
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RESPONSE --> Maybe I should've added more in my answer, but I did the steps exactly right. self critique assessment: 3
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21:13:29 `q011. If it is known that y = k x^-2 and that when x = 5, y = 250, then what value of y will correspond to x = 12?
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RESPONSE --> Y = 6250 * 12^-2 = 6250 / 12^2 = 6250 / 144 = 42.6 confidence assessment: 2
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18:17:36 Substituting x = 5 and y = 250 into the form y = k x^-2 we obtain 250 = k * 5^-2. Since 5^-2 = 1 / 5^2 = 1/25, this becomes 250 = 1/25 * k, so that k = 250 * 25 = 6250. Thus our form y = k x^-2 becomes y = 6250 x^-2. When x = 12, we therefore have y = 6250 * 12^-2 = 6250 / 12^2 = 6250 / 144 = 42.6, approximately.
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RESPONSE --> Got it. self critique assessment: 3
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