Assignment 19

course Mth 163

? ?????H?a??q|assignment #019

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019. `query 19

Precalculus I

11-07-2007

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11:12:46

explain the steps in fitting an exponential function to data

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RESPONSE -->

For exponential data one should plot log(y) vs. x. If the graph is a straight line then the person will have a good fit.

If the slope is m and the vertical intercept is b the graph would be log(y) = m x + b.

Then invert the transformation using the inverse function (10^x), getting the equation 10^log(y) = 10^(mx+b).

Therefore,

y = 10^(mx) * 10^b

confidence assessment: 3

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12:13:02

** If you have two points you can solve the simultaneous equations. If you have a more extensive data set you use transformations.

For exponential data you plot log(y) vs. x. If the graph is a straight line then you have a good fit.

If the slope is m and the vertical intercept is b then your graph gives you log(y) = m x + b.

You invert the transformation using the inverse function 10^x, obtaining 10^log(y) = 10^(mx+b) so that

y = 10^(mx) * 10^b, and then rearrange this into the desired form.

Note that if a power function fits the data then log y vs. log x will give a straight line so that log y = m log x + b. In this case our solution will be y = 10^b * x^m, a power function rather than an exponential function. **

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RESPONSE -->

I got it. I still need to work my explaining skills.

You're doing well.

self critique assessment: 3

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Very good work. Let me know if you have questions. &#