cq_1_021

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PHY 201

Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball starts with velocity 4 cm/sec and ends with a

velocity of 10 cm/sec.

What is your best guess about the ball's average

velocity?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

I would guess around 7 cm/sec. This is the average of

the two stated velocities. (Initial + Final)/2

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Without further information, why is this just a guess?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

The definition of average velocity is the change in

position divided by the change in clock time. This

information is missing.

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If it takes 3 seconds to get from the first velocity to

the second, then what is your best guess about how far

it traveled during that time?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

The approximate distance covered in this time would be

21 cm. Change in position = average velocity * time.

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At what average rate did its velocity change with

respect to clock time during this interval?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

This would be the average acceleration, by definition

average acceleration = average velocity / change in

time. 7 cm/s / 3 sec = 2.33 cm/s^2

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@& 7 cm/s is average velocity, not change in velocity. The calculation of the average rate of change of velocity with respect to clock time requires the change in velocity.

Good attempt, and you made a very common error; just make sure you understand.*@

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Solution

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