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PHY 201
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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For each situation state which of the five quantities
v0, vf, `ds, `dt and a are given, and give the value of
each.
A ball accelerates uniformly from 10 cm/s to 20 cm/s
while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 10 cm/s
vf = 20 cm/s
'ds = 45 cm
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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds,
and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
a = 10 cm/s^2
'dt = 3 seconds
vf = 50 cm/s
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A ball travels 30 cm along an incline, starting from
rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
'ds = 30 cm
v0 = 0 cm/s
a = 20 cm/s^2
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Then for each situation answer the following:
Is it possible from this information to directly
determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
For the first it is possible to solve for vAve directly
by (vf + v0)/2 = vAve. For the second and third there
will be a subsequent step.
For the second question it is v0 = vf - a*'dt, then (vf
+ v0)/2 = vAve.
For the third, vf^2 = v0^2 + 2*a*'ds then (vf + v0)/2 =
vAve.
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Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> :
For the first yes, vf - v0 = 'dv. For the second and
third there will be a subsequent step.
For the second question it is v0 = vf - a*'dt, then vf -
v0 = 'dv.
For the third, vf^2 = v0^2 + 2*a*'ds then vf - v0 = 'dv.
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*#&!
&#Very good responses. Let me know if you have questions. &#