#$&*
PHY 201
Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
A ball accelerates uniformly as it rolls 20 cm down a
ramp, starting from rest, in 2 seconds.
What are its average velocity, final velocity and
acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve='ds/'dt
vAve=20cm/2s=10cm/s.
'ds=((vf+v0)/2)*'dt,
(2'ds/dt)-v0=vf,
((2*20cm)/2s)-0cm/s=vf,
20cm/s=vf.
#$&*
If the time interval is in error so that it is 3%
longer than the actual time interval, then what are
the actual values of the final velocity and
acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve='ds/'dt
vAve=20cm/2.06s=9.71cm/s.
'ds=((vf+v0)/2)*'dt,
(2'ds/dt)-v0=vf,
((2*20cm)/2.06s)-0cm/s=vf,
19.4cm/s=vf.
#$&*
What is the percent error in each?
answer/question/discussion: ->->->->->->->->->->->-> :
%error=((value-result)/value)*100,
%=(10cm/s-9.71cm/s)/10cm/s * 100,
@& You have calculated the percent error in average velocities, not in accelerations.*@
% = 2.9 percent error in aAve.
%error=((value-result)/value)*100,
% = (20cm/s-19.4cm/s)/20cm/s * 100,
% = 2.9 percent error in vf.
#$&*
If the percent error is the same for both velocity and
acceleration, explain why this must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
I don't understand what the question is asking. Why
what must be so? Why the percent error must be so?
The percent error would be the same because of the
error in time. Both are dependant upon the observed
time.
#$&*
If the percent errors are different explain why it
must be so.
answer/question/discussion: ->->->->->->->->->->->-> :
#$&*
** **
15 minutes
@& You have calculated percent errors in average velocity and final velocity,.
You have not yet calculated or found percent errors in acceleration.
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*@