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PHY 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle,
which consists of a complete back-and-forth
oscillation (extreme point to equilibrium to opposite
extreme point back to equilibrium and finally to the
original extreme point). As long as the amplitude of
the motion (the amplitude is the distance from the
equilibrium position to the extreme point) is small
compared to the length of the pendulum, the time
required for a cycle is independent of the amplitude.
How long does it take to get from one extreme point to
the other, how long from an extreme point to
equilibrium, and how long to go from extreme point to
equilibrium to opposite extreme point and back to
equilibrium?
1 second from one extreme point to the other, .5
seconds from an extreme point to equilibrium, and 1.5
seconds from one extreme point equilibrium to opposite
extreme point and back to equilibrium.
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answer/question/discussion: ->->->->->->->->->->->-> :
What reasonable assumption did you make to arrive at
your answers?
I assumed the pendulum was travelling without losing
any momentum.
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@& The average speed, and therefore the average magnitude of the momentum of the pendulum clearly decreases with every cycle.
I believe your implicit assumption was the the time intervals between 'strikes' were the same.
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&#Good responses. See my notes and let me know if you have questions. &#