open query 2

course mth 151

Question: `q2.2.24 U={a,b,...,g}, A={a,e}, B={a,b,e,f,g}, C={b,f,g}, D={d,e} Is C ps U? vvvv

Is the statement true or false and why?

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Your solution:

True. Because all the elements from C are in U.

confidence rating: 3

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Given Solution:

`a** It's true because all elements of C are in the universal set, and because there are elements of U that aren't in C. You have to have both conditions, since a proper subset cannot be identical to other set. **

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Self-critique (if necessary):

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Question: `qQuery 2.2.30 phi s D

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Your solution:

False.

confidence rating: 2

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Given Solution:

`a** Note that You should be responding to problem 2.2.30 from the homework you worked out on paper. The shorthand notation is for my reference and won't always make sense to you. For clarification, though, the symbol for the empty set is the Greek letter phi.

One set is a subset of another if every element of that set is in the other. To show that a set isn't a subset of another you have to show something in that set that isn't in the other.

There's nothing in the empty set so you can never do this--you can never show that it has something the other set doesn't. So you can never say that the empty set isn't a subset of another set.

Thus the empty set is a subset of any given set, and in particular it's a subset of D.

ALTERNATIVE ANSWER: As the text tells you, the empty set is a subset of every set.

ANOTHER ALTERNATIVE

Every element of the empty set is in D because there is no element in the empty set available to lie outside of D.

ONE MORE ALTERNATIVE: The empty set is a subset of every set. Any element in an empty set is in any set, since there's nothing in the empty set to contradict that statement. **

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Self-critique (if necessary):

I was very confused on that one.

&#Your response did not agree with the given solution in all details, and you should therefore have addressed the discrepancy with a full self-critique, detailing the discrepancy and demonstrating exactly what you do and do not understand about the parts of the given solution on which your solution didn't agree, and if necessary asking specific questions (to which I will respond).

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Question: `q2.2.33 D not s B

Is the statement true or false and why?

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Your solution:

True. D only has d and e, but B has a,b,e,f, and g. d is not in B at all and D does not have a, b, or f.

confidence rating: 3

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Given Solution:

`a** D is a subset of B if every element of D is an element of B-i.e., if D doesn't contain anything that B doesn't also contain.

The statement says that D is not a subset of B. This will be so if D contains at least one element that B doesn't. **

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Self-critique (if necessary):

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Question: `q2.2.36 there are exactly 31 subsets of B

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Your solution:

No. because the subsets are doubled and this one would be 2^5 because there are 5 elements in B, which would come to 32.

confidence rating: 3

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Given Solution:

`a** If a set has n elements then is has 2^n subsets, all but one of which are proper subsets. B has 5 elements so it has 2^5 = 32 subsets. So the statement is false.

There are exactly 31 proper subsets of B, but there are 32 subsets of B. **

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Self-critique (if necessary):

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Question: `qQuery 2.2.40 there are exactly 127 proper subsets of U

Is the statement true or false and why?

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Your solution:

True. 2^7= 128 subsets and 128-1= 127 proper subsets.

confidence rating: 3

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Given Solution:

`a** The set is not a proper subset of itself, and the set itself is contained in the 2^n = 2^7 = 128 subsets of this 7-element set. This leaves 128-1 = 127 proper subsets. **

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Self-critique (if necessary):

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Question: `qQuery 2.2.48 U={1,2,...,10}, complement of {2,5,7,9,10}

What is the complement of the given set?

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Your solution:

1,3,4,6,8 would be the compliment.

confidence rating: 3

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Given Solution:

`a** the complement is {1,3,4,6,8}, the set of all elements in U that aren't in the given set. **

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Self-critique (if necessary):

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Question: `qquery 2.2.63 in how many ways can 3 of the five people A, B, C, D, E gather in a suite?

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Your solution:

I think there are at least 10 subsets. (abc) (abd) (abe) (ace) (ade) (dec) (bcd) (bed) (bce) (acd)

confidence rating: 3

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Given Solution:

`a** The answer here would consist of a list of all 3-element subsets: {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d} etc. There are ten such subsets.

Using a,b,c,d,e to stand for the names, we can list them in alphabetical order:

{a,b,c), {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e|, {b,c,d}, {b,c,e}, {b,d,e}, {c, d, e}**

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&#Good responses. See my notes and let me know if you have questions. &#