course Phy 201 jwr„¼ķ{Ż·¬ųąäŹājł¦īŗassignment #001
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14:03:44 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> First you get the average of the set of numbers given, then you take the average and square root it giving you the standard deviation. confidence assessment: 3
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14:11:15 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> First you have to place the points given on the graph, then by taking a ruler draw a straight line through the data on the graph. A good straight line graph will not go directly through any of the data points but will come close. Two different people could get different results depending on how well their corrdinances are compared to the actual ones. Even if off by a .5 the slope will still be different. The vertical intercept is basically just an imaginary line drawn and an educated guess so the chances of being different are again very high. confidence assessment: 2
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14:18:17 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is used to figure out how fast an object is moving and the direction of the objects travel. Velocity is a rate because no every velocity for each object is going to be the same and for each interval or trial the velocity will change. Therefore, you take the velocity's average to get the rate change. confidence assessment: 1
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14:19:59 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> The rate of change of position would be change in position/change in clock time self critique assessment: 0
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14:25:46 Given average speed and time interval how do you find distance moved?
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RESPONSE --> I'm not very sure. I think I got this wrong on the questions also. confidence assessment: 0
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14:26:46 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> Thanks! self critique assessment: 3
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14:27:47 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> Time = Distance moved - Average speed confidence assessment: 1
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14:30:03 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> Thanks! self critique assessment: 2
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14:30:43 Given time interval and distance moved how do you get average speed?
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RESPONSE --> Average speed= distance/time confidence assessment: 3
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14:31:08 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> self critique assessment: 3
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