#$&*
PHY 232
Your 'question form' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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I am having trouble with problem set 6, problem number 9.
I understand that:
v = 'omega * 'lambda
or
velocity = frequency * wavelength
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I understand that velocity is given. However in the solution where frequency pops up, I don't know how that was deduced. I can't seem to reproduce that frequency with the given information in the problem description.
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How was frequency determined? Or was it just given?
omega is the angular frequency, not the frequency. Frequency is in cycles/second, angular frequency in radians/second. The connection is that a cycle is 2 pi radians, so omega = 2 pi * frequency.
In the problem as it currently shows the frequency and velocity are given. The current problem reads
'Find the equation of motion for a particle at x = 6.1 for a transverse sine wave which propagates in the x direction at 76 m/s. The frequency of the wave is 221 Hz, and its amplitude is .277 meters. Assume that the x=0 particle has equation of motion y = A sin(`omega t).'
You didn't include a copy of the problem as you saw it; it's possible some information was not included in that version, though I'm not aware of any omission related to this problem.