course mth 152 ޶ħx‰ô§¨k|ó¶vâ•ò vÁ³êôùäBÙéassignment #014
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08:42:21 query problem 13.1.6 freq dist 35 IQ scores class width 5
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RESPONSE --> 90-95 1 1/50=.02 96-100 3 3/50=.06 101-105 5 5/50=.10 106-110 7 7/50=.14 111-115 12 12/50=.24 116-120 9 9/50=.18 121-125 7 7/50=.14 126-130 4 4/50=.08 131-135 2 2/50=.04
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08:42:21 query problem 13.1.6 freq dist 35 IQ scores class width 5
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RESPONSE -->
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08:43:31 ** These numbers might or might not be completely accurate, but the calculation of the relative frequencies as percents follows from the tallies: 91-95 1 1/50 = 2% 96-100 3 3/50 = 6% 101-105 5 5/50 = 10% 106-110 7 7/50 = 14% 111-115 12 12/50 = 24% 116-120 9 9/50 = 18% 121-125 8 8/50 = 16% 126-130 3 3/50 = 6% 131-135 2 2/50 = 4% **
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RESPONSE --> I did not enter my answers in percentage form, I left them in decimal form but I got the answers right.
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09:02:45 query problem 13.1.10 stem and leaf for yards gained by 44 rushers
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RESPONSE --> 0 7 3 1 9 2 8 6 2 8 2 4 9 9 5 3 6 7 3 9 0 6 3 2 4 5 3 3 0 2 1 9 6 5 4 8 1 5 6 7 0 2 7 3 9 3 8 8 6 9 4 10 2 11 2 12 3
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09:03:12 ** In order we get the following: 0 3 7 1 2 6 8 9 2 2 4 5 8 9 9 3 0 2 3 3 6 6 7 9 4 0 1 2 3 3 5 6 9 5 1 4 5 8 6 0 2 7 7 3 3 9 8 6 8 9 4 10 2 11 2 12 3 **
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RESPONSE --> That is what mine looks like.
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09:08:51 query problem 13.1.35 empirical probability distribution for letters of alphabet
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RESPONSE --> A - .08/.385 = .21=21% E - .13/.385 = .34=34% I - .065/.385 =.17=14% O - .08/.385 = .21=21% U - .03/.385 =.08=8% A bar graph would probably be the best way to display the results.
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09:09:28 ** The probabilities for A, E, I, O, U are: .08. .13, .065, .08, .03. The sum of these probabilities is .385 The probabilities of the letters given a vowel: .08 / .385 = .208 .13 / .385 = .338 .065 / .385 = .169 .08 / .385 = .208 .03 / .385 = .078 These probabilities total 1. **
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RESPONSE --> I gave the percentage this time and I figured a bar graph would best illustrate the outcome
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course mth 152 ޶ħx‰ô§¨k|ó¶vâ•ò vÁ³êôùäBÙéassignment #014
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08:42:21 query problem 13.1.6 freq dist 35 IQ scores class width 5
......!!!!!!!!...................................
RESPONSE --> 90-95 1 1/50=.02 96-100 3 3/50=.06 101-105 5 5/50=.10 106-110 7 7/50=.14 111-115 12 12/50=.24 116-120 9 9/50=.18 121-125 7 7/50=.14 126-130 4 4/50=.08 131-135 2 2/50=.04
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08:42:21 query problem 13.1.6 freq dist 35 IQ scores class width 5
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RESPONSE -->
.................................................
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08:43:31 ** These numbers might or might not be completely accurate, but the calculation of the relative frequencies as percents follows from the tallies: 91-95 1 1/50 = 2% 96-100 3 3/50 = 6% 101-105 5 5/50 = 10% 106-110 7 7/50 = 14% 111-115 12 12/50 = 24% 116-120 9 9/50 = 18% 121-125 8 8/50 = 16% 126-130 3 3/50 = 6% 131-135 2 2/50 = 4% **
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RESPONSE --> I did not enter my answers in percentage form, I left them in decimal form but I got the answers right.
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09:02:45 query problem 13.1.10 stem and leaf for yards gained by 44 rushers
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RESPONSE --> 0 7 3 1 9 2 8 6 2 8 2 4 9 9 5 3 6 7 3 9 0 6 3 2 4 5 3 3 0 2 1 9 6 5 4 8 1 5 6 7 0 2 7 3 9 3 8 8 6 9 4 10 2 11 2 12 3
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09:03:12 ** In order we get the following: 0 3 7 1 2 6 8 9 2 2 4 5 8 9 9 3 0 2 3 3 6 6 7 9 4 0 1 2 3 3 5 6 9 5 1 4 5 8 6 0 2 7 7 3 3 9 8 6 8 9 4 10 2 11 2 12 3 **
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RESPONSE --> That is what mine looks like.
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09:08:51 query problem 13.1.35 empirical probability distribution for letters of alphabet
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RESPONSE --> A - .08/.385 = .21=21% E - .13/.385 = .34=34% I - .065/.385 =.17=14% O - .08/.385 = .21=21% U - .03/.385 =.08=8% A bar graph would probably be the best way to display the results.
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09:09:28 ** The probabilities for A, E, I, O, U are: .08. .13, .065, .08, .03. The sum of these probabilities is .385 The probabilities of the letters given a vowel: .08 / .385 = .208 .13 / .385 = .338 .065 / .385 = .169 .08 / .385 = .208 .03 / .385 = .078 These probabilities total 1. **
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RESPONSE --> I gave the percentage this time and I figured a bar graph would best illustrate the outcome
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