course Mth 152 ɵVĦM̳捔Ϭassignment #015
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10:42:31 query problem 13.2.10 .3, .4, .3, .8, .7, .9, .2, .1, .5, .9, .6
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RESPONSE --> a) .3+.4+.3+.8+.7+.9+.2+.1+.5+.9+.6=5.7/11 =.5 b) .1, .2, .3, .3, .4, .5, .6, .7, .8, .9, .9 .5 is the median c) 3 and 9
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10:43:23 ** The numbers, in order, are .1, .2, .3, .3, .4, .5, .6, .7, .8, .9, .9 The mean, obtained by adding the 11 numbers then dividing by 11, is .518. The median occurs at position (n + 1 ) / 2 = 6 in the ordered list. This number is .5. Note that there are five numbers before .5 and five numbers after .5. The maximum number of times a number repeats in this distribution is 2. So there are two modes (and we say that the distribution is bimodal). The modes are .3 and .9. **
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RESPONSE --> That is what I got. I just looked at the median instead of working it like you have to see if there was a middle number.
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10:46:04 **** query problem 13.2.24 more effect from extreme value
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RESPONSE --> The mean would be effected more and the median less
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10:47:41 ** The mean is drastically affected by the error; correcting the error changes the mean by about 3 units. The median number, however, simply shifts 1 position, changing from 2.28 to 2.39. **
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RESPONSE --> I didn't think the median would be affected very much but the decimal has an effect on the mean.
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10:52:06 **** query problem 13.2.30 Salaries 6 @$19k, 8 @ 23k, 2 @ 34.5k, 7 @ 56.9k, 1 @ 145.5k.
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RESPONSE --> 6 * 19,000 = 114,000 8 * 23,000 = 184,000 2 * 34,500 = 69,000 7 * 56,900 = 398,300 1*145,500 = 145,500 910,800/24= $37.950.00
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10:53:45 ** IF THERE ARE 28 EMPLOYEES: The totals paid for each salary level are: 6 * $19,500 = $117,000 8 * $23,000 = $184,000 4 * $28,300 = $113,200 2 * $34,500 = $69,000 7 * $36,900 = $258,300 1 * $145,500 = $145,500 The grand total paid in salaries to the 28 employees is therefore $887,000, giving an average of $887,000 / 28 = $31,700. The median occurs at position (n + 1) / 2 = (28 + 1) / 2 = 14.5. Since the 14 th salaray on a list ordered from least to greatest is $23,000 and the 15 th is $28300 the median is ($23000 +$28300) / 2 = $25,650. The mode is 23,000, since this salary occurs more frequently than any other. IF THERE ARE 24 EMPLOYEES: The totals paid for each salary level are: $19,000 * 6 = $114,000 $23,000 * 8 = $184,000 $34,500 * 2 = $69,000 $56,900 * 7 = $398,300 $145,500 * 1 = $145,500 Adding these gives a grand total, which is divided by the number 24 of employees to obtain the mean $37,950. The median occurs at position (n + 1) / 2 = (24 + 1) / 2 = 12.5. Since the $23000 salary covers positions 7 thru 14 in an ordered lise of salaries the median is $23,000. The mode is 23,000, since this salary occurs more frequently than any other.
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RESPONSE --> I got 24 employees and I only gave the mean answer.
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10:58:42 **** query problem 13.2.51 mean, med, mode of 0, 1, 3, 14, 14, 15, 16, 16, 17, 17, 18, 18, 18, 19, 20
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RESPONSE --> 15 total numbers 0+1+3+(14*2)+15+(16*2)+(17*2)+(18*3)+19+20= 0+1+3+28+15+32+34+54+19+20=206/15= 13.73 Mean - 13.73 16+17=33/2=16.5 Median - 16.5 Mode - 18
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10:59:06 ** The mean is 13.73, obtained by adding together all the numbers and dividing by n = 15. The median is in position (n+1) / 2 = (15+1)/2 = 8 on the ordered list; the 8 th number is 16. The mode is 18, which is the only number occurring as many as 3 times. **
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RESPONSE --> That is what I got.
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10:59:41 **** Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> I kinda of enjoyed this section. It takes a little bit of time to do but I actually understand it.
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course Mth 152 ɵVĦM̳捔Ϭassignment #015
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10:42:31 query problem 13.2.10 .3, .4, .3, .8, .7, .9, .2, .1, .5, .9, .6
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RESPONSE --> a) .3+.4+.3+.8+.7+.9+.2+.1+.5+.9+.6=5.7/11 =.5 b) .1, .2, .3, .3, .4, .5, .6, .7, .8, .9, .9 .5 is the median c) 3 and 9
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10:43:23 ** The numbers, in order, are .1, .2, .3, .3, .4, .5, .6, .7, .8, .9, .9 The mean, obtained by adding the 11 numbers then dividing by 11, is .518. The median occurs at position (n + 1 ) / 2 = 6 in the ordered list. This number is .5. Note that there are five numbers before .5 and five numbers after .5. The maximum number of times a number repeats in this distribution is 2. So there are two modes (and we say that the distribution is bimodal). The modes are .3 and .9. **
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RESPONSE --> That is what I got. I just looked at the median instead of working it like you have to see if there was a middle number.
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10:46:04 **** query problem 13.2.24 more effect from extreme value
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RESPONSE --> The mean would be effected more and the median less
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10:47:41 ** The mean is drastically affected by the error; correcting the error changes the mean by about 3 units. The median number, however, simply shifts 1 position, changing from 2.28 to 2.39. **
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RESPONSE --> I didn't think the median would be affected very much but the decimal has an effect on the mean.
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10:52:06 **** query problem 13.2.30 Salaries 6 @$19k, 8 @ 23k, 2 @ 34.5k, 7 @ 56.9k, 1 @ 145.5k.
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RESPONSE --> 6 * 19,000 = 114,000 8 * 23,000 = 184,000 2 * 34,500 = 69,000 7 * 56,900 = 398,300 1*145,500 = 145,500 910,800/24= $37.950.00
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10:53:45 ** IF THERE ARE 28 EMPLOYEES: The totals paid for each salary level are: 6 * $19,500 = $117,000 8 * $23,000 = $184,000 4 * $28,300 = $113,200 2 * $34,500 = $69,000 7 * $36,900 = $258,300 1 * $145,500 = $145,500 The grand total paid in salaries to the 28 employees is therefore $887,000, giving an average of $887,000 / 28 = $31,700. The median occurs at position (n + 1) / 2 = (28 + 1) / 2 = 14.5. Since the 14 th salaray on a list ordered from least to greatest is $23,000 and the 15 th is $28300 the median is ($23000 +$28300) / 2 = $25,650. The mode is 23,000, since this salary occurs more frequently than any other. IF THERE ARE 24 EMPLOYEES: The totals paid for each salary level are: $19,000 * 6 = $114,000 $23,000 * 8 = $184,000 $34,500 * 2 = $69,000 $56,900 * 7 = $398,300 $145,500 * 1 = $145,500 Adding these gives a grand total, which is divided by the number 24 of employees to obtain the mean $37,950. The median occurs at position (n + 1) / 2 = (24 + 1) / 2 = 12.5. Since the $23000 salary covers positions 7 thru 14 in an ordered lise of salaries the median is $23,000. The mode is 23,000, since this salary occurs more frequently than any other.
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RESPONSE --> I got 24 employees and I only gave the mean answer.
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10:58:42 **** query problem 13.2.51 mean, med, mode of 0, 1, 3, 14, 14, 15, 16, 16, 17, 17, 18, 18, 18, 19, 20
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RESPONSE --> 15 total numbers 0+1+3+(14*2)+15+(16*2)+(17*2)+(18*3)+19+20= 0+1+3+28+15+32+34+54+19+20=206/15= 13.73 Mean - 13.73 16+17=33/2=16.5 Median - 16.5 Mode - 18
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10:59:06 ** The mean is 13.73, obtained by adding together all the numbers and dividing by n = 15. The median is in position (n+1) / 2 = (15+1)/2 = 8 on the ordered list; the 8 th number is 16. The mode is 18, which is the only number occurring as many as 3 times. **
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RESPONSE --> That is what I got.
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10:59:41 **** Query Add comments on any surprises or insights you experienced as a result of this assignment.
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RESPONSE --> I kinda of enjoyed this section. It takes a little bit of time to do but I actually understand it.
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