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Phy 241
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
Sketch a straight line segment between these points.
What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise of this segment is 30 cm/sec.
Rise = 40 cm/s - 10 cm/s = 30 cm/s
Run = 9 seconds - 4 seconds = 5 seconds
Rise/Run = slope = 30 cm/s / 5 sec = 6 cm/s /sec
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Good.
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What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The area of the graph beneath this segment is 75 cm/s.
.5 * (30 cm/sec * 5 sec) = 75 cm
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The area beneath the graph is a trapezoid, not a triangle.
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