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Phy 241
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_06.1_labelMessages **
For each situation state which of the five quantities v0, vf, `ds, `dt and a are given, and give the value of each.
A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 10 cm/s
vf = 20 cm/s
ds = 45 cm
dt = ds/vAve
dt = 45 cm /((10 cm/s + 20 cm/s)/2)
dt = 45 cm /15 cm/s
dt = 3 sec
a = dv/dt
a = (20 cm/sec -10 cm/s) / 3 sec
a = 10 cm/sec /3 sec
a = 3.33 cm
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A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> :
a = 10 cm/sec^2
dt = 3 sec
vf = 50 cm/sec
v0 = vf - adt
v0 = 50 cm/sec - (10 cm/sec^2 * 3 sec)
v0 = 50 cm/sec - 30 cm/sec
v0 = 20 cm/sec
ds = v0dt + .5adt^2
ds = (20 cm/sec * 3 sec) + (.5(10 cm/sec^2) * (3 sec))
ds = 60 cm + 45 cm
ds = 105 cm
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A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 0 cm/sec
ds = 30 cm
a = 20 cm/sec^2
vf = sqrt(v0^2 + 2ads)
vf = sqrt(2 * 20 cm/sec * 30 cm)
vf = sqrt(1200 cm^2/sec^2)
vf = 34.64 cm/sec
ds = 30 cm/ (34.64 cm/sec / 2)
ds = 30 cm/17.32 cm/sec
ds = 1.73 sec
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Then for each situation answer the following:
Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> :
It is possible for question 3
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Is it possible to directly determine `dv?
It is possible for question 1 and 2
answer/question/discussion: ->->->->->->->->->->->-> :
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