ph1 query 2

course Phy 121

6/29 12 PM

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

002. `ph1 query 2

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Question: Explain how velocity is defined in terms of rates of change.

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Your solution:

In terms of rates of change, velocity is defined as vAve = `ds / `dt. This means that the average velocity is the change in distance divided by the change in time, or the change in distance with respect to the change in time.

Confidence Assessment: 3

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Given Solution: Average velocity is defined as the average rate of change of position with respect to clock time.

The average rate of change of A with respect to B is (change in A) / (change in B).

Thus the average rate of change of position with respect to clock time is

• ave rate = (change in position) / (change in clock time).

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Self-critique (if necessary):

I should have used the term “position” instead of “distance” in my definition. `ds = change in position, not change in distance.

Self-critique Rating: 3

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Question: Why can it not be said that average velocity = position / clock time?

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Your solution:

Average velocity is not equal to position / clock time because it should read average velocity = AVERAGE position / AVERAGE clock time.

Confidence Assessment: 3

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Given Solution: The definition of average rate involves the change in one quantity, and the change in another.

Both position and clock time are measured with respect to some reference value. For example, position might be measured relative to the starting line for a race, or it might be measured relative to the entrance to the stadium. Clock time might be measure relative to the sound of the starting gun, or it might be measured relative to noon.

So position / clock time might, at some point of a short race, be 500 meters / 4 hours (e.g., 500 meters from the entrance to the stadium and 4 hours past noon). The quantity (position / clock time) tells you nothing about the race.

There is a big difference between (position) / (clock time) and (change in position) / (change in clock time).

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Self-critique (if necessary):

Self-critique Rating:

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Question: Give your solution to the following, which should be in your notes: Find the approximate uncertainty in the area of a circle given that its radius is 2.8 * 10^4 cm.

STUDENT COMMENT: I understand how squaring the problem increases uncertainty and I understand the concept of

a range of uncertainty but I am having trouble figuring out how the range of 2.75 * 10^4 and 2.85*10^4 were established

for the initial uncertainties in radius.

INSTRUCTOR RESPONSE:

The key is the first sentence of the given solution:

'Radius 2.8 * 10^4 cm means that the radius is between 2.75 * 10^4 cm and 2.85 * 10^4 cm.'

You know this because you know that any number which is at least 2.75, and less than 2.85, rounds to 2.8.

Ignoring the 10^4 for the moment, and concentrating only on the 2.8:

Since the given number is 2.8, with only two significant figures, all you know is that when rounded to two significant figures the quantity is 2.8. So all you know is that it's between 2.75 and 2.85.

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Your solution:

2.8 * 10^4 can mean anywhere between 2.75 * 10^4 and 2.85 * 10^4 because of rounding (2.75 is rounded to 2.8, as is any number between 2.75 and 2.85).

The formula for finding area of a circle is A = pi * r^2

If the radius is 2.75 * 10^4, then A = pi * (2.75 * 10^4)^2 = pi * (756250000) = 2.376 * 10^9 cm^2.

If the radius is 2.85 * 10^4, then A = pi * (2.85 * 10^4)^2 = pi * (812250000) = 2.552 * 10^ 9 cm^2.

(2.552 * 10^9 cm^2) – (2.376 * 10^9 cm^2) = 0.176 * 10^9 cm^2

The approximate uncertainty is 0.176 * 10^9 cm^2

Confidence Assessment: 2

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Given Solution:

** Radius 2.8 * 10^4 cm means that the radius is between 2.75 * 10^4 cm and 2.85 * 10^4 cm.

This means that the area is between pi * (2.75 * 10^4 cm)^2 = 2.376 * 10^9 cm^2 and pi * (2.85 * 10^4 cm)^2 = 2.552 * 10^9 cm^2. The difference is .176 * 10^9 cm^2 = 1.76 * 10^8 cm^2, which is the uncertainty in the area.

Note that the .1 * 10^4 cm uncertainty in radius is about 4% of the radius, which the .176 * 10^9 cm uncertainty in area is about 8% of the area. This is because the area is proportional to the squared radius. A small percent uncertainty in the radius gives very nearly double the percent uncertainty in the squared radius. **

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Self-critique (if necessary):

0.176 * 10^9 cm^2 is not correct scientific notation. The decimal needs to be moved to the right by one place so that the number reads 1.76 * 10^8 cm^2.

Self-critique Rating:3

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Question: What is your own height in meters and what is your own mass in kg? Explain how you determined these? What are your uncertainty estimates for these quantities, and on what did you base these estimates?

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Your solution:

My height: 4’11” or 59 in.

1 in = 2.54 cm

59 in * 2.54 cm = 149.86 cm

100 cm = 1 m

149.86 cm / 100 cm = 1.4986 m

My weight: 125 lbs

1 lb = 453.59237 g

125 lbs * 453.59237 g = 56699.04625 g

1 kg = 1000 g

56699.04625 g / 1000 g = 56.69904625 kg

I determined these answers by converting my height in inches to centimeters, then to meters. I converted my weight in pounds to grams, then to kilograms. My answers are uncertain due to significant figures.

Confidence Assessment: 3

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Given Solution:

Presumably you know your height in feet and inches, and have an idea of your ideal weight in pounds. Presumably also, you can convert your height in feet and inches to inches.

To get your height in meters, you would first convert your height in inches to cm, using the fact that 1 inch = 2.54 cm. Dividing both sides of 1 in = 2.54 cm by either 1 in or 2.54 cm tells us that 1 = 1 in / 2.54 cm or that 1 = 2.54 cm / 1 in, so any quantity can be multiplied by 1 in / (2.54 cm) or by 2.54 cm / (1 in) without changing its value.

Thus if you multiply your height in inches by 2.54 cm / (1 in), you will get your height in cm. For example if your height is 69 in, your height in cm will be 69 in * 2.54 cm / (1 in) = 175 in * cm / in.

in * cm / in = (in / in) * cm = 1 * cm = cm, so our calculation comes out 175 cm.

STUDENT SOLUTION

5 feet times 12 inches in a feet plus six inches = 66 inches. 66inches * 2.54 cm/inch = 168.64 cm. 168.64 cm *

.01m/cm = 1.6764 meters.

INSTRUCTOR COMMENT:

Good, but note that 66 inches indicates any height between 65.5 and 66.5 inches, with a resulting uncertainty of about .7%.

168.64 implies an uncertainty of about .007%.

It's not possible to increase precision by converting units.

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Self-critique (if necessary):

Self-critique Rating:

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