course Phy 232 Jg̪QQfwӠ܍assignment #004
......!!!!!!!!...................................
22:49:32 Query introductory set #1, 10-17 Explain how to find the potential difference in volts between two given points on the x axis, due to a given charge at the origin.
......!!!!!!!!...................................
RESPONSE --> subtract volts of first point from volts of second. volts at the point is found by (k * q)/r where q is the charge at the origin and r is the distance the point is from that charge (in this case the point's x coordinate) confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:49:53 ** Potential difference is the work per Coulomb of charge moved between the two points. To find this work you can multiply the average force on a Coulomb of charge by the displacement from the first point to the second. You can find an approximate average force by finding the force on a 1 Coulomb test charge at the two points and averaging the two forces. Multiplying this ave force by the displacement gives an approximate potential difference. Since the force is not a linear function of distance from the given charge, if the ratio of the two distances from the test charge is not small the approximation won't be particularly good. The approximation can be improved to any desired level of accuracy by partitioning the displacement between charges into smaller intervals of displacement and calculating the work done over each. The total work required is found by adding up the contributions from all the subintervals. University Physics students should understand how this process yields the exact w ""ork, which is the integral of the force function F(x) = k Q / x^2 between the two x values, yielding total work W = k * Q * 1 Coulomb ( 1 / x1 - 1 / x2) and potential difference V = k * Q ( 1 / x1 - 1 / x2). **
......!!!!!!!!...................................
RESPONSE --> this seems more complex than what I put. self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:51:35 Explain how to find the potential difference between two points given the magnitude and direction of the uniform electric field between those points.
......!!!!!!!!...................................
RESPONSE --> volts are equal to magnitude of the electric field multiplied by the displacement between them. confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:52:21 ** The work per Coulomb done between the two points is equal to the product of the electric field E and the displacement `dr. Thus for constant field E we have V = E * `dr. **
......!!!!!!!!...................................
RESPONSE --> what is the difference between multiplying by the magnitude of the elec field and mult. by the elec field? they are one in the same if you include the +/- in there, right? self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:57:38 Explain how to find the average electric field between two points given a specific charge and the work done on the charge by the electric field as the charge moves between the points.
......!!!!!!!!...................................
RESPONSE --> Work done/displacement is the average force field strength is (work done/displacement)/strength of charge (dW/ds)/Q confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:57:52 ** You get ave force from work and distance: F_ave = `dW / `ds. You get ave electric field from work and charge: E_ave = F / q. An alternative: Find potential difference `dV = `dW / q. Ave electric field is Eave = `dV / `ds **
......!!!!!!!!...................................
RESPONSE --> ok! self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:59:36 In your own words explain the meaning of voltage.
......!!!!!!!!...................................
RESPONSE --> work per coloumb to move a charge r units. confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:59:47 ** Voltage is the work done per unit of charge in moving charge from one point to another. **
......!!!!!!!!...................................
RESPONSE --> ok self critique assessment: 2
.................................................
"