#$&*
Phy 201
Your 'energy conversion 1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** Energy Conversion 1_labelMessages **
** **
Answer in comma-delimited format in the first line below. Give a brief explanation of the meaning of your numbers starting in the second line.
Your answer (start in the next line):
23.3 cm, 180 degrees
I pined a point with a dot and then shot the domino, I guessed on the degrees I did use a protractor but it was still difficult to measure
#$&* _ 2 rb tension how far and thru what angle
Tape the paper to the tabletop, or otherwise ensure that it doesn't move during subsequent trials.
• Repeat the previous instruction until you have completed five trials with the rubber band at same length as before.
Report your results in the same format as before, in 5 lines. Starting in the sixth line give a brief description of the meaning of your numbers and how they were obtained:
Your answer (start in the next line):
25.3cm, 0
24.5cm, 90
23.9cm, 0
24.7cm, 80
25.3 0
it was difficult to measure the degrees but I did what I did before for the distance.
#$&* _ trials on paper
Now, without making any marks, pull back a bit further and release.
• Make sure the length of the rubber band doesn't exceed its original length by more than 30%, with within that restriction what rubber band length will cause the block to slide a total of 5 cm, then 10 cm, then 15 cm.
• You don't need to measure anything with great precision, and you don't need to record more than one trial for each sliding distance, but for the trials you record:
• The block should rotate as little as possible, through no more than about 30 degrees of total rotation, and
• it should slide the whole distance, without skipping or bouncing along.
• You can adjust the position of the rubber band that holds the block together, the angle at which you hold the 'tail', etc., to eliminate skipping and bouncing, and keep rotation to a minimum.
Indicate in the first comma-delimited line the rubber band lengths that resulted in 5 cm, 10 cm and 15 cm slides. If some of these distances were not possible within the 30% restriction on the stretch of the rubber band, indicate this in the second line. Starting in the third line give a brief description of the meaning of these numbers.
Your answer (start in the next line):
6.1 cm, 5.6 cm, 6.3 cm, 6.7cm, 5.9 cm
9.9cm, 8.9cm, 7.9 cm, 10.1 cm, 9.7cm
14.3, 15.2, 16.3cm, 14.5cm, 15.1 cm
it was difficult to measure the distance without having the 2 points. using the ruler I measured the beginning to the end
#$&* _ rb lengths for 5, 10, 15 cm slides
Now record 5 trials, but this time with the rubber band tension equal to that observed (in the preceding experiment) when supporting 4 dominoes. Mark and report only trials in which the block rotated through less than 30 degrees, and in which the block remained in sliding contact with the paper throughout.
Report your distance and rotation in the same format as before, in 5 lines. Briefly describe what your results mean, starting in the sixth line:
Your answer (start in the next line):
15.6cm,
16.7cm,
16.8,
14.5cm,
16.3cm
shooting with 4 dominos I was able to measure it started from to the point it ended at
#$&* _ 5 trials 4 domino length
Repeat with the rubber band tension equal to that observed when supporting 6 dominoes and report in the same format below, with a brief description starting in the sixth line:
Your answer (start in the next line):
11.1
12.6
12.8
12.2
10.2
with more dominos and the more weight the dominos did not travel as far these measurements were taken in cm
#$&* _ 5 trials for 6 domino length
Repeat with the rubber band tension equal to that observed when supporting 8 dominoes and report in the same format below, including a brief description starting in the sixth line:
Your answer (start in the next line):
6.7,
5.9,
6.1,
5.6
6.1
I tried to use the same force and got even shorter distances with 8 dominoes so more weight and less force the dominos travel a less distance
#$&* _ 5 trials for 8 domino length
Repeat with the rubber band tension equal to that observed when supporting 10 dominoes and report in the same format below, including your brief description as before:
Your answer (start in the next line):
4.5
5.9
4.2
4.6
4.1
theses dominos traveled the least because they had the most weight
#$&* _ 5 trials for 10 domino length
In the preceding experiment you calculated the energy associated with each of the stretches used in this experiment.
The question we wish to answer here is how that energy is related to the resulting sliding distance.
• For each set of 5 trials, find the mean and standard deviation of the 5 distances. You may use the data analysis program or any other means you might prefer.
• In the space below, report in five comma-delimited lines, one for each set of trials, the length of the rubber band, the number of dominoes supported at this length, the mean and the standard deviation of the sliding distance in cm, and the energy associated with the stretch.
• You might choose to report energy here in Joules, in ergs, in Newton * cm or in Newton * mm. Any of these choices is acceptable.
• Starting in the sixth line specify the units of your reported energy and a brief description of how your results were obtained. Include your detailed calculations and specific explanation for the third interval. Be sure to give a good description of how you obtained the energy associated with each stretch:
Your answer (start in the next line):
There are 5 numbers in your distribution.
Their sum is 23.3
Their mean is 23.3/ 5 = 4.66.
The (mean) average deviation from the mean is .4960.
The sum of the squared deviations is 2.092.
The standard deviation is therefore sqrt( 2.092/( 5 - 1) ) = .7232
#$&* _ for each set of trials length, # dom, mean, std of sliding dist, energy _ describe how results obtained esp energy calculations
Sketch a graph of sliding distance vs. energy, as reported in the preceding space .
• Fit the best possible straight line to your graph, and give in the first comma-delimited line the slope and vertical intercept of your line.
• In the second line specify the units of the slope and the vertical intercept.
• Starting in the third line describe how closely your data points cluster about the line, and whether the data points seem to indicate a straight-line relationship or whether they appear to indicate some sort of curvature.
• If curvature is indicated, describe whether the curvature appears to indicate upward concavity (for this increasing graph, increasing at an increasing rate) or downward concavity (for this increasing graph, increasing at a decreasing rate).
Your answer (start in the next line):
There are 5 numbers in your distribution.
Their sum is 23.3
Their mean is 23.3/ 5 = 4.66.
The (mean) average deviation from the mean is .4960.
The sum of the squared deviations is 2.092.
The standard deviation is therefore sqrt( 2.092/( 5 - 1) ) = .7232
#$&* _ sliding dist vs. energy slope, vert intercept of st line, how close to line, describe curvature if any
1 hour.