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phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Copy the problem below into a text editor or word processor.
• This form accepts only text so a text editor such as Notepad is fine.
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You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
4 cm/s + 10 cm/s = 14 cm/s / 2 =
7 cm/s is the average speed.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This is just a guess because I do not have the amount of time the ball rolled to accurately calculate the average speed.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The ball probably traveled between 12 cm and 30 cm.
I calculated the distance for each given velocity in 3 seconds.
If the ball was going at 4 cm/s, it would cover 12 cm in 3 seconds and if the ball was going at 10 cm/s, it would cover 30 cm in 3 seconds.
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Average rate = change in velocity / change in time
Average rate = 6 cm/sec / 3 sec = 2 cm/sec/sec
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15 minutes
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&#Very good responses. Let me know if you have questions. &#