cq_1_091

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phy 201

Your 'cq_1_09.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A ball accelerates uniformly as it rolls 20 cm down a ramp, starting from rest, in 2 seconds. 

• What are its average velocity, final velocity and acceleration? 

answer/question/discussion: ->->->->->->->->->->->-> :

 vAve = 20 cm / 2 s

vAve = 10 cm/s

10 cm/s = (0 m/s + vf) / 2

20 cm/s = vf

aAve = (20 cm/s - 0 m/s) / 2 s

aAve = 10 cm/s/s

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• If the time interval is in error so that it is 3% longer than the actual time interval, then what are the actual values of the final velocity and acceleration? 

answer/question/discussion: ->->->->->->->->->->->-> :

 vAve = 20 cm / 2.06 s

vAve = 9.70 cm/s

9.70 cm/s = (0 m/s + vf) / 2

19.4 cm/s = vf

aAve = (19.4 cm/s - 0 m/s) / 2.06 s

aAve = 9.42 cm/s/s

• What is the percent error in each? 

answer/question/discussion: ->->->->->->->->->->->-> :

accepted value - measured value /divided by/ accepted value

 Vf: (20 cm/s - 19.4 cm/s) / 20 cm/s = .03 * 100 = 3.0 %

aAve : (10 cm/s/s - 9.42 cm/s/s) / 10 cm/s/s = .058 * 100 = 5.8 %

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• If the percent error is the same for both velocity and acceleration, explain why this must be so. 

answer/question/discussion: ->->->->->->->->->->->-> :

 The percent error for vf and aAve I calculated are not the same.

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• If the percent errors are different explain why it must be so.

answer/question/discussion: ->->->->->->->->->->->-> :

 # I am not sure. The 3 % change impacted one quantity more so than the other.

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15 minutes

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Solution

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