phy 201
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> : aveage rate=change in A/change in B, so this would be ave. rate=`da/`dslope. to get `da, you find `dv first. `ds/`dt=10m/8s=1.25m/s, and 10m/5s=2m/s.
a=1.25m/s/8s=0.16m/s^2 and a=2m/s/5s=0.4m/s^s so `da=.4-.26=0.24m/s^2 and finally, average rate =0.24m/s^2/0.05=4.8 (change in slope being .10-.05=.05)
I know there are issues with this, but I can’t seem to get it to work out right either in my head or on paper. I don’t think I got the correct values for `dv to use in finding a, and can’t figure out even with notes how to get `dv from the information given.
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1 hour, maybe more
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You pretty much got this, except that your calculation of the accelerations had one flaw (you divided vAve by `dt, not `dv by `dt). Good try. No need for a revision as long as you understand:
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