course PHY 201

Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s velocity changes at a uniform rate from 10 cm/s to 13 cm/s as

it travels 46 cm, then what is the average acceleration of the object?

Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which accelerates through a distance

of 46 cm, starting from velocity 10 cm/s and accelerating at .75 cm/s/s.

aAve = (vf-v0)/ `dt

aAve = (13-10)/4

aAve = 0.75 cm/s^2

v0= 10cm/s

vf = 13cm/s

`ds = 46 cm

`dt = 4s

The numbers for the second question will be the same as the first question.