cal_a8_quiz2

course MTh 173

Write the differential equation expressing the hypothesis that the rate of change of a population is proportional to the population P. Evaluate the proportionality constant if it is known that the when the population is 2433 its rate of change is known to be 200. If this is the t=0 state of the population, then approximately what will be the population at t = 1.9? What then will be the population at t = 3.8?200 = k(2433)

K = 0.082

`dp/`dt = 0.082(2433*t)

=0.082 (2433*1.9)

= 379

dp/dt = k * P, not k * P * t, and not k * P * `dt (it's not completely clear which you intend).

You get dp/dt = .082 * 2433, which gives you the rate of change of p with respect to t at t = 0.

Then you multiply dp/dt by the time interva `dt (not by the clock time t, though since the initial instant is t = 0, the clock time and the time interval are identical, for the first interval only). This provides an estimate of the change in p.

Adding the change in p to the original value of p we get the estimated new value of p, i.e., the value at t = 1.9.

Base on our estimate of p, we evaluate dp/dt again, using the t = 1.9 values.

Then we proceed, based on this value, to make an estimate for the new interval, based on `dt = 1.9.

=0.082 (2433*3.8)

= 758

This estimate of dp/dt is based on the rate of change at t = 0 and the clock time after two intervals of duration 1.9 units. We wouldn't ordinarily mix the values in this way.

This is unlikely to lead to a good estimate.

I'm also appending a similar problem with a worked-out solution, for your reference:

Write the differential equation expressing the hypothesis that the rate of

change of an investment is proportional to the principal P.

y is proportional to x if there exists a constant

number k, called the proportionality constant, such that y = k x.

The rate of change of quantity P with respect to clock

time t is dP/dt.

The differential equation is therefore

dP/dt = k P

Evaluate the proportionality constant if it is known that the when the

principal is 3353 its rate of change is 400.

The principal in the equation above is P and its rate

of change is dP/dt.  Thus dP/dt = 400 when P = 3353 so the equation dP/dt =

k P becomes

400 = k * 3353, so that the value of the

proportionality constant k is

k = 400 / 3353 = .12, approx.

Thus the rate of change of the principle is given in

terms of the principle by

dP/dt = .12 P.

If this is the t=0 value of the principal, then approximately what will be

the principal at t = 1.1?

The rate of change at t = 0 is 400.  Assuming that

this rate continues over the interval from t = 0 to t = 1.1, the change in

principle will be

`dP = change in principle = rate of change * `dt = 400

* 1.1 = 440.

That is, the principle will increase by about 440. 

Having started at P = 3353, the new principle will be

P(1.1) = P(0) + `dP = 3353 + 440 = 3793.

  What then will be the principal at t

= 2.2?

Assuming that the principle at t = 1.1 is 3793, we have

new rate of change of principle = dP/dt = .12 P = .12 *

3793 = 456.

If the principle changes at this rate during the

interval from t = 1.1 to t = 1.2 the principle will increase by

`dP = change in principle = rate of change * `dt = 456

* 1.1 = 500, approx..

Thus our new principle at t = 2.2 is

P(2.2) = P(1.1) + `dP = 3793 + 500 = 4293.

These approximations are based on the assumption that

the rate of change of principle remains constant for the 1.1-unit time

intervals.  In this case the rate increases with population, so these

approximations are underestimates.

(if you are bothered by the fact that k is approximated

to only two significant figures, while the changes in principal are calculated

to 3 significant figures, you are correct; significant figures should be

considered here but in this solution the instructor has chosen not to address

this issue)

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