Phy 121
Your 'cq_1_08.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball is tossed upward with an initial velocity of 25 meters / second. Assume that the acceleration of gravity is 10 m/s^2 downward.
• What will be the velocity of the ball after one second?
answer/question/discussion: ->->->->->->->->->->->-> :
vf=v0 + at
vf= 25 m/s + -10 m/s^2 (1)
vf= 15 m/s
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• What will be its velocity at the end of two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
vf= 25m/s +-10 m/s^2(2)
vf=25m/s + -20 m/s
vf=5 m/s
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• During the first two seconds, what therefore is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
25 m/s + 5 m/s = 30 m/s
30m/s divided by 2
15 m/s
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• How far does it therefore rise in the first two seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
20 m
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• What will be its velocity at the end of a additional second, and at the end of one more additional second?
answer/question/discussion: ->->->->->->->->->->->-> :
25 m/s + 10 m/s^2 (3)
25m/s – 30 m/s
-5m/s
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• At what instant does the ball reach its maximum height, and how high has it risen by that instant?
answer/question/discussion: ->->->->->->->->->->->-> :
When it reaches 0 meters per second. 47.5 meters
It should reach 0 m/s in 2.5 s. Averaging 12.5 m/s it should rise to a height of a little over 30 m.
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• What is its average velocity for the first four seconds, and how high is it at the end of the fourth second?
answer/question/discussion: ->->->->->->->->->->->-> :
15 m/s
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• How high will it be at the end of the sixth second?
answer/question/discussion: ->->->->->->->->->->->-> :
#$&*
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30 minutes
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I was slightly confused by this question.
You did very well. You should see the link, but revision is requested only if you have questions and/or want me to check your work.
&#Please compare your solutions with the expanded discussion at the link
Solution
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