Phy 121
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
• What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
mv^2/r=f
110 grams* 30 cm/sec^2/ 20 cm=f
110 gram*900 cm/sec / 20 cm=f
(99,000 gram cm ^2 / sec ^2) / 20 cm=f
4,950 N
Good calculation, but the units would be grams * cm / sec^2, not Newtons.
A Newton is a kg m/s^2. The result would be .0495 N.
#$&*
• What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> :
The force would have to be stronger than the friction.
#$&*
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10 min
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&#Please compare your solutions with the expanded discussion at the link
Solution
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