course Phy201 Was there really only one question for general physics on this query? Or did my program mess up? yUB۽؍zDassignment #003
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14:22:35 Query Principles of Physics and General College Physics: Summarize your solution to Problem 1.19 (1.80 m + 142.5 cm + 5.34 `micro m to appropriate # of significant figures)
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RESPONSE --> First I convert all the measurements to meters as follows: 1.80 m = 1.80 m 142cm = 1.42 m 5.34 *10^5 um = .534 m 1.8 + 1.42 + .534 = 3.754 m Round to 3 significant figures Answer: 3.75 m confidence assessment: 2
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14:25:28 ** 1.80 m has three significant figures (leading zeros don't count, neither to trailing zeros unless there is a decimal point; however zeros which are listed after the decimal point are significant; that's the only way we have of distinguishing, say, 1.80 meter (read to the nearest .01 m, i.e., nearest cm) and 1.000 meter (read to the nearest millimeter). Therefore nothing smaller than .01 m can be distinguished. 142.5 cm is 1.425 m, good to within .001 m. 5.34 * `micro m means 5.34 * 10^-6 m, or .00000534 m, accurate to within .00000001 m. When these are added you get 3.22500534 m; however the 1.80 m is not resolved beyond .01 m so the result is 3.23 m. Remaining figures are meaningless, since the 1.80 m itself could be off by as much as .01 m. **
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RESPONSE --> The book gave the third quantity as 5.34 *10^-5 um, not as 5.34 um self critique assessment: 2
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14:26:09 University Physics #34: Summarize your solution to Problem 1.34 (4 km on line then 3.1 km after 45 deg turn by components, verify by scaled sketch).
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RESPONSE --> not applicable to general physics confidence assessment: 3
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