cq_1_021

PHY 201

Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.

• What is your best guess about the ball's average velocity?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

2 cm / sec

#$&*

• Without further information, why is this just a guess?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

There is no time interval to compare the velocity change too.

#$&*

• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

18 cm’s, The difference between the two velocities is 6 cm/sec and it traveled for 3 seconds then 6*3 = 18.

#$&*

• At what average rate did its velocity change with respect to clock time during this interval?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

2 cm’s per second is the average rate, because the change in velocity divided by the change in clock time is: 6 cm per sec / 3 sec’s = 2 cm’s per second

#$&*

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20 minutes

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I believe this has already been posted. Let me know if there's a difference between this and your posted document.

cq_1_021

A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.

• What is your best guess about the ball's average velocity?

answer/question/discussion (start in the next line):

2 cm / sec

This answer is incorrect. Be sure you compare with the link provided at the end of this document.

#$&*

• Without further information, why is this just a guess?

answer/question/discussion (start in the next line):

There is no time interval to compare the velocity change too.

#$&*

• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that

time?

answer/question/discussion (start in the next line):

18 cm’s, The difference between the two velocities is 6 cm/sec and it traveled for 3 seconds then 6*3 = 18.

This answer is incorrect. Be sure you compare with the link provided at the end of this document.

#$&*

• At what average rate did its velocity change with respect to clock time during this interval?

answer/question/discussion (start in the next line):

2 cm’s per second is the average rate, because the change in velocity divided by the change in clock time is: 6 cm per sec / 3 sec’s = 2 cm’s

per second

#$&*

&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.

If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#