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Phy 201
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_01.1_labelMessages **
The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on an interval is
average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure to identify the quantity A, the quantity B and the requested average rate.
If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Since the ball changes from 10 to 20 cm the change in A will be 10cm.
20cm - 10cm = 10cm = Change in A
Since the clock time changes from 4sec to 9sec the change in B will be 5sec.
9sec - 4sec = 5sec = Change in B
Average Rate of Change = 10cm/5sec
Average Rate of Change = 2cm/sec
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If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The Change in A can be found by subtracting the two given velocities.
40cm/sec - 10cm/sec = 30cm/sec
Average Rate of Change = 30cm/sec / 3sec
Average Rate of Change = 10cm
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Good, but your units aren't correct.
If you divide cm/s by s you get
(cm/s) / s = (cm/s) * (1/s) = cm/s^2.
not cm.
*@
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If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The position changes 50cm.
According to the Average Rate of Change formula AVC = (Change in A)/(Change in B).
Therefore if the Change in B is 10 seconds and the final result is 5 cm/sec then 50cm/10sec = 5cm/sec.
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You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The easiest way for me to remeber the definition for Average Rate of Change is to think of a simple x and y axis and remember that the x axis which most likely represents time is on the bottom while the y axis which mostly represents distance is on top.
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You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The definition of average rate of change is applied by finding the change in distance and the change in time of the object and then dividing change in distance by change in time. Think of a graph and remember that change in time is on the bottom like the x axis and the change in distance is on top like the y axis.
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&#Your work looks good. See my notes. Let me know if you have any questions. &#