cq_1_101

#$&*

Phy 121

Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

________________________________________

A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.

• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?

From one extreme point to another - 1 s

Extreme point to equilibrium - .5 s

Extreme to equilibrium - .5 s

Extreme point to opposite extreme point - 1 s

Extreme point to opposite extreme point to equilibrium - 1.5 s

#$&*

answer/question/discussion: ->->->->->->->->->->->-> :

• What reasonable assumption did you make to arrive at your answers?

That the pendulum traveled at a uniform velocity and you could break the points into segments and divide the total time to get time increments.

#$&*

*#&!

@& RIght idea, but note that the pendulum has a uniform period, not a uniform velocity. Its velocity is constantly changing.*@

*#&!

&#Very good responses. Let me know if you have questions. &#