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Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
On the 5 kg side, the force will be 5 kg * 9.8 N = 49 N
On the 6 kg side, the force will be 6 kg * 9.8 N = 58.8 N
Since the two are on a pulley the forces would work against one another with…
58.8 N - 49 N = 9.8 N
For acceleration…
9.8 N / 11 kg = .89 m/s^2 in the downward direction for the 6 kg side.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
5 kg * 9.8 N = 49 N + 1.8 N = 50.8 N
6 kg * 9.8 N = 58.8 N
Net force = 58.8 N - 50.8 N = 8 N
8 N / 11 kg = .73 m/s in the downward direction for the 6 kg side
The 5 kg mass would be lifted .73 m and would be traveling at .73 m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
The velocity would momentarily be going in the downward direction of the 5 kg side at first due to the push, but it would be accelerating in the opposite direction in favor of a downward direction on the 6 kg side due to the net force being in its favor. The system would slow down until it stopped.
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&#Your work looks very good. Let me know if you have any questions. &#