#$&*
Phy 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
________________________________________
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
• What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
I did not have a good calculator when I did this, so I found an online calculator that measured the angles if I could put in at least 2 measurements. I put 2 in as the x point, for the base of the right triangle, and 3 for the y, at the top of the right triangle.
The magnitude is 5 N at 56.31 degrees (the B angle at the top of the right triangle)
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• What are the components of the equilibrant force?
-2 N, -3 N
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• What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
-5 n and 180 degrees - 56.31 degrees = 123.69 degrees
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*#&!
@& If the x component of a force is negative then its angle is arcTan(y comp / x comp) + 180 degeees.
The arctangent of (-3 N / (-2 N) ) is arctan(3/2) = 56 degrees, not -56 degrees.*@
*#&!*#&!
@& Good. Check my note.
Just in case you need it for reference:
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
*@
#$&*
Phy 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
________________________________________
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
• What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis?
I did not have a good calculator when I did this, so I found an online calculator that measured the angles if I could put in at least 2 measurements. I put 2 in as the x point, for the base of the right triangle, and 3 for the y, at the top of the right triangle.
The magnitude is 5 N at 56.31 degrees (the B angle at the top of the right triangle)
#$&*
• What are the components of the equilibrant force?
-2 N, -3 N
#$&*
• What angle does the equilibrant force make as measured counterclockwise from the positive x axis?
-5 n and 180 degrees - 56.31 degrees = 123.69 degrees
#$&*
*#&!
@& If the x component of a force is negative then its angle is arcTan(y comp / x comp) + 180 degeees.
The arctangent of (-3 N / (-2 N) ) is arctan(3/2) = 56 degrees, not -56 degrees.*@
*#&!*#&!
@& Good. Check my note.
Just in case you need it for reference:
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#
*@