#$&*
Phy 121
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
________________________________________
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
.06 kg * .8 m/s = .048 kg m/s (before)
.06 * .5 m/s = .03 kg m/s
.02 kg * .7 m/s = .014 kg m/s
.03 kg m/s + .014 kg m/s = .044 kg m/s (after)
It is slightly less.
#$&*
• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
For the initial momentum to match the after collision momentum the marble would have to be going 73 cm/s or its mass would have to be 55 g.
#$&*
*#&!*#&!
&#Very good responses. Let me know if you have questions. &#