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Phy 121
Your 'cq_1_26.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A simple pendulum has length 2 meters. It is pulled back 10 cm from its equilibrium position and released. The tension in the string is 5 Newtons.
• Sketch the system with the pendulum mass at the origin and the x axis horizontal.
answer/question/discussion: ->->->->->->->->->->->-> :
The pendulum is at equilibrium at center. The tension on the string at 5 N = 0 since it is its equilibrium point.
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• Sketch a vector representing the direction of the pendulum string at this instant. As measured from a horizontal x axis, what is the direction of this vector? (Hint: The y component of this vector is practically the same as the length; you are given distance of the pullback in the x direction. So you know the x and y components of the vector.)
answer/question/discussion: ->->->->->->->->->->->-> :
x component = cos(.1 m) = .999
y component = sin(2 m) = .035
direction = tan^-1(.035 / .1) = 19.29 deg
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• What is the direction of the tension force exerted on the mass?
answer/question/discussion: ->->->->->->->->->->->-> :
x component = cos(5 N) = .996
y component = sin(5N) = .0872
direction = tan^-1(.0872 / .996) = 5 deg.
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• What therefore are the horizontal and vertical components of the tension?
answer/question/discussion: ->->->->->->->->->->->-> :
horizontal .996
vertical - .0872
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• What therefore is the weight of the pendulum, and what it its mass?
answer/question/discussion: ->->->->->->->->->->->-> :
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• What is its acceleration at this instant?
answer/question/discussion: ->->->->->->->->->->->-> :
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Solution
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