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Phy 121
Your 'cq_1_01.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_01.1_labelMessages **
The problem:
Here is the definition of rate of change of one quantity with respect to another:
The average rate of change of A with respect to B on aninterval is
average rate of change of A with respect to B = (change in A) / (change in B)
Apply the above definition of average rate of change of A with respect to B to each of the following. Be sure toidentify the quantity A, the quantity B and the requestedaverage rate.
If the position of a ball rolling along a track changes from 10 cm to 20 cm while the clock time changes from 4 seconds to 9 seconds, what is the average rate of change of its position with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate of change of the balls position with respect to the clock time is 2 centimeters per second. Found this by the difference of (20-10) 10 centimeters divided by the time difference of (9-4) 5 which gave us 2 cm/s. Quantity A is the difference in ball position and quantity B is the difference in time.
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If the velocity of a ball rolling along a track changes from 10 cm / second to 40 cm / second during an interval during which the clock time changes by 3 seconds, then what is the average rate of change of its velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rate of change of the rolling balls velocity with respect to the time is 10cm/second. This is because the difference in velocity is (40-10) 30 divided by the change in time 3 to give us 10 cm/s. Quantity A is the difference in velocity and quantity B is the difference in time.
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Good, but your units aren't correct.
Units should be included at every step. Your calculation would be
(40 cm/s - 10 cm/s) / (3 s) = (30 cm/s) / (3 s) = 30 cm/s * 1/s = 30 cm/s^2.
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If the average rate at which position changes with respect to clock time is 5 cm / second, and if the clock time changes by 10 seconds, by how much does the position change?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The position changes by 50 centimeters. This is because you multiply the 5 cm/s times 10 seconds to get 50 cm. Quantity A is the difference in position, which is what we are trying to fine and quantity B is the difference in time.
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You will be expected hereafter to know and apply, in a variety of contexts, the definition given in this question. You need to know this definition word for word. If you try to apply the definition without using all the words it is going to cost you time and it will very likely diminish your performance. Briefly explain how you will ensure that you remember this definition.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
I will ensure that I remember this definition by writing it many times. I am a very visual learner and the more times I write it the easier it is to see.
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You are asked in this exercise to apply the definition, and given a general procedure for doing so. Briefly outline the procedure for applying this definition, and briefly explain how you will remember to apply this procedure.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The procedure for this definition is the (change in a)/(change in b) with respect of b. I will remember this by writing it multiple times.
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&#Good responses. See my notes and let me know if you have questions. &#