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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m*a
Fnet = 12kg * 3m/s^2
Fnet = 36kg*m/s^2
Fnet = 36 Newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m*a
20N = 4kg * a
20kg*m/s^2 = 4kg * a
5m/s^2 = a
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m*a
Fnet = 10kg * 1.5m/s^2
Fnet = 15kg*m/s^2
Fnet = 15 Newtons
If the object is 10kg and moving at an acceleration of 1.5m/s^2 it would only require a net force of 15 Newtons, but because you are exerting a force of 20 Newtons this means that there is 5 Newtons of force opposing your movement.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
The total of the forces is 15 Newtons because you exert 20 Newtons and there is 5 Newtons opposing you so, 20N-5N = 15N.
The direction that these forces act on is positive in the given situation.
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&#Very good responses. Let me know if you have questions. &#