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Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Copy the problem below into a text editor or word processor.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
-The net force will be 9.8N because 58.8N - 49N = 9.8N.
-The acceleration will be -.89m/s^2 because it is descending on the side with 6kg.
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
-The final velocity in this scenario would be .91m/s because since the system is moving down its acceleration will be negative, so:
vf = v0 + a * ‘dt
vf = 1.8m/s + -.89m/s^2 * 1s
vf = 1.8m/s - .89m/s
vf = .91m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
The velocity and acceleration are in opposite directions and the system is slowing down.
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This looks very good. Let me know if you have any questions.