#$&*
Phy 121
Your 'cq_1_16.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
cq_1_161
#$&*
Phy 121
Your 'cq_1_16.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Copy the problem below into a text editor or word processor.
This form accepts only text so a text editor such as Notepad is fine.
You might prefer for your own reasons to use a word processor (for example the formatting features might help you organize your answer and explanations), but note that formatting will be lost when you submit your work through the form.
If you use a word processor avoid using special characters or symbols, which would require more of your time to create and will not be represented correctly by the form.
As you will see within the first few assignments, there is an easily-learned keyboard-based shorthand that doesn't look quite as pretty as word-processor symbols, but which gets the job done much more efficiently.
You should enter your answers using the text editor or word processor. You will then copy-and-paste it into the box below, and submit.
________________________________________
A rubber band has no tension until it reaches a length of 7.5 cm. Beyond that length its tension increases by .7 Newtons for every additional centimeter of length.
What will be its tension if its endpoints are at the points (5 cm, 9 cm) and (10 cm, 17 cm) as measured on an x-y coordinate system?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The tension will be approximately 1.4N because the length of the line is 9.43cm, as found by the Pythagorean theorem (5^2+8^2=89 and sqrt(89)=1.93).
#$&*
What is the vector from the first point to the second?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The vector from the first point is 9.43cm.
#$&*
@&
That is the magnitude of the vector.
You also need to specify its direction, either by giving its components or its angle with the positive x axis.
*@
&&&&The angle of this vector is 53.13 degrees in relation to the positive x axis.&&&&&
What is the magnitude of this vector?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The magnitude of this vector is 9.43cm.
#$&*
What vector do you get when you divide this vector by its magnitude? (Specify the x and y components of the resulting vector).
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The vector divided by its magnitude is as follows:
9.43cm/9.43cm=1cm.
@&
The vector has a magnitude and a direction. If you divide a vector by a positive number, its direction does not change.
*@
#$&*
The new vector should have magnitude 1. When you divide a vector by its magnitude the result is a vector with magnitude 1. We call a vector of magnitude 1 a unit vector. What vector do you get when you multiply this new vector (i.e., the unit vector) by the tension?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
When you multiply the unit vector by 1.4N, you get 1.4N because 1*1.4N = 1.4N.
@&
If you have found the components of the unit vector, you can multiply those components by 1.4 Newtons to find the components of the force vector.
*@
#$&*
What are the x and y components of the new vector?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> :
The component of this vector is .9 and the y component is 1.2.
?????I really dont understand how you find this?????
#$&*
@&
Think of Introductory Problem Set 5.
What are the x and y components of a vector of magnitude 1.4 Newtons at angle 53 degrees?
*@
*#&!*#&!*#&!
@&
Good, but you need to find some components. Check my notes.
*@