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Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion:
What are the x and y components of the equilibrant of the force?
answer/question/discussion:
The force x components are:
X = 10 cos (250degrees) = -3.4
Y = 10 sin (250degrees) = -9.4
Based on magnitude 10 and 250 degree angle
The equilibrant of the force will be equal and opposite:
X = 3.4 and Y = 9.4
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10 mins
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&#This looks very good. Let me know if you have any questions. &#