open query 22

#$&*

course mth 151

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

002. `Query 2

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Question: `q2.2.24 U={a,b,...,g}, A={a,e}, B={a,b,e,f,g}, C={b,f,g}, D={d,e}

Is the statement 'C is not a proper subset of U' true or false and why?

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Your solution:

This is false because C is a proper subset of U, because all the elements of C are in U but not all of U elements are in C. C is the universal set of elements. It takes both U and C being identical.

confidence rating #$&*:

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Given Solution:

`a** The statement is false.

C is a proper subset of U because all elements of C are in the universal set, and because there are elements of U that aren't in C. Note that it takes both of these conditions to make U a proper subset of C, since a proper subset cannot be identical to other set. **

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Self-critique (if necessary):

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Question: `qQuery 2.2.30 phi s D

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Your solution:

The empty set is nothing, so you cannot say that the empty set is not subset of another set, being that it The empty set is a subset of any given set, so this means it is a subset of D.

confidence rating #$&*:

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Given Solution:

`a** Note that You should be responding to problem 2.2.30 from the homework you worked out on paper. The shorthand notation is for my reference and won't always make sense to you. For clarification, though, the symbol for the empty set is the Greek letter phi.

One set is a subset of another if every element of that set is in the other. To show that a set isn't a subset of another you have to show something in that set that isn't in the other.

There's nothing in the empty set so you can never do this--you can never show that it has something the other set doesn't. So you can never say that the empty set isn't a subset of another set.

Thus the empty set is a subset of any given set, and in particular it's a subset of D.

ALTERNATIVE ANSWER: As the text tells you, the empty set is a subset of every set.

ANOTHER ALTERNATIVE

Every element of the empty set is in D because there is no element in the empty set available to lie outside of D.

ONE MORE ALTERNATIVE: The empty set is a subset of every set. Any element in an empty set is in any set, since there's nothing in the empty set to contradict that statement. **

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q(2.2.31, previously 2.2.33)

Is the following statement true or false:

D is not a subset of B

Is the statement true or false and why?

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Your solution:

This is a true statement, D is a subset of B. D contains every element that B has.

confidence rating #$&*:

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Given Solution:

`a** D is a subset of B if every element of D is an element of B-i.e., if D doesn't contain anything that B doesn't also contain.

The statement says that D is not a subset of B. This will be so if D contains at least one element that B doesn't. **

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Question: `q2.2.34 (previously 2.2.36) there are exactly 31 subsets of B

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Your solution:

In a set of elements it has 2^n subsets, and all but one of the subsets are proper, B has 5 elements so it would be 2^5=32 so this would make this statement false. There are 31 subsets of B and the equation says it should be 32.

confidence rating #$&*:

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Given Solution:

`a** If a set has n elements then is has 2^n subsets, all but one of which are proper subsets. B has 5 elements so it has 2^5 = 32 subsets. So the statement is false.

There are exactly 31 proper subsets of B, but there are 32 subsets of B. **

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Question: `qQuery 2.2.38

Is the statement true or false and why?

There are exactly 128 proper subsets of U

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Your solution:

U is not a proper subset, the set is 2^n which is 2^7=128 subsets of the 7 element set. Then you would take 128-1=127 proper subsets. This means that there are not 128 proper subsets in this set.

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confidence rating #$&*:

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Given Solution:

`a** The set is not a proper subset of itself, and the set itself is contained in the 2^n = 2^7 = 128 subsets of this 7-element set. This leaves 128-1 = 127 proper subsets.

So thre are not 128 proper subsets of this set.**

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Self-critique (if necessary):

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Question: `qQuery 2.2.45 U={1,2,...,10}. What is the complement of {1, 2, 3, 4, 6, 8}?

(previously 2.2.48 complement of {2,5,7,9,10} )

What is the complement of the given set?

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Your solution:

{1,2,3,4,6,8} these are the set of elements in U that are the in the given set. The elements 5,7,9 and 10 are not in the given set but are in U, so the complement is {5,7,9,10}

confidence rating #$&*:

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Given Solution:

`a** the complement is {1,2,3,4,6,8}, the set of all elements in U that aren't in the given set.

The elements 5, 7, 9and 10 are not in the given set but are in U, so the complement is the set

{5, 7, 9, 10}**

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Question: `qquery 2.2.59 in how many ways can 3 of the five people A, B, C, D, E gather in a suite?

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Your solution:

{a,b,c},{a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e}, {b,c,d}, {b,c,e}, {b,d,e}, {c,d,e}, I believe that there are 10 different ways of having 3 of the five people in a group.

confidence rating #$&*:

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Given Solution:

`a** The answer here would consist of a list of all 3-element subsets: {a,b,c}, {a,b,d}, {a,b,e}, {a,c,d} etc. There are ten such subsets.

Using a,b,c,d,e to stand for the names, we can list them in alphabetical order:

{a,b,c), {a,b,d}, {a,b,e}, {a,c,d}, {a,c,e}, {a,d,e|, {b,c,d}, {b,c,e}, {b,d,e}, {c, d, e}**

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Question: `q (previously 2.1.74) (formerly 2.1.72) This was not assigned, but you should be able to answer based on your work on similar problems: It is or is it not true that 2 is not not subset of {7,6,5,4}?

 

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Your solution:

This statement would be true because 2 is not a set, it is just a number, it is not a set so it cannot be used for anything. In order to have a subset you must have a set.

confidence rating #$&*:

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Given Solution:

`a** The statement is that 2 is not a subset. The statement is true because 2 isn't even a set, it's just a number. {2} is a set and could be a subset of something. 2 is just a number; it isn't a set so it can't be a subset of anything.

The usual answer is that 2 isn't a subset because 2 isn't in the set. However that's not the correct reason. The correct reason is that 2 isn't a set and a subset must be a set.

COMMON MISCONCEPTION: the statement says that 2 is not a subset, not that it is not an element of the set. So the reason it's not a subset is that 2 isn't a set at all, so it can't be a subset of anything. **

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Question: `q (previously 2.1.86) (formerly 2.1.84). This was not assigned but you should be able to answer this.

If C={4,10,12} and B={2,4,8,10}:

Is it true or false that every element of C is also an element of B? Be sure to include your reasoning.

 

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Your solution:

False because 12 is an element of C but not B.

confidence rating #$&*:

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Given Solution:

`a** Specifically it's false because the element 12 is in C but not in B. **

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q (previously 2.1.86) (formerly 2.1.84). This was not assigned but you should be able to answer this.

If C={4,10,12} and B={2,4,8,10}:

Is it true or false that every element of C is also an element of B? Be sure to include your reasoning.

 

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Your solution:

False because 12 is an element of C but not B.

confidence rating #$&*:

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Given Solution:

`a** Specifically it's false because the element 12 is in C but not in B. **

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Self-critique (if necessary):

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Self-critique rating:

#*&!

&#Good work. Let me know if you have questions. &#