PHY 121
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : (13+5)/2 = 9seconds
• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : (40+16)/2 = 28cm/s
• How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : at least 144cm but no more than 360.
• By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 13-5 = 8 seconds.
• By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 24cm/s
&#Good, but you have an error with your units. &#
• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> : (24cm/s)/(8s) = 3cm/s
• What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 24
• What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 8
• What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : rise/run = 24/8 = 3
• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : The object is moving in a positive direction and is increasing in speed.
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : (24cm/s)/(8s) = 3cm/s
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20 minutes
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Very good. However your units aren't always correct, and it is essential that you use units and actually do the algebra of units. Not that hard to learn ends up saving a lot of time by catching a lot of errors. Check the link:
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#