PHY 121
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : v0 = 0. Vf = 2m/.64s = 3.13m/s. a = 3.13m/s/.64s = 4.9m/s^2
• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> : v0 = 0. Vf = 5m/1.05s = 4.8m/s. 4.8m/s/1.05s = 4.6m
• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> : No; there are lots of factors that influence acceleration. The accepted value of acceleration is for an object in a vacuum.
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10 minutes
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Acceleration is `dv / `dt, not vAve / `dt.
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Solution
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