PHY 121
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answer/question/discussion: a of .05 incline = .8m/s/8 = .64m/s^2
a of .10 incline = 2m/s/5s = .4m/s^2
.64-.4= .24m’s^2 decrease in acceleration per .05 increase in incline.
-- I’m not sure I got at what the question was asking for, but this is what made sense to me. I don’t completely understand why an object at a greater incline would have a smaller acceleration that an object at a lesser incline. Is it because the object at the greater incline will reach its maximum speed sooner? I’m not sure.
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15 minutes
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