course PHY 121 I definitely understand the first part of the question but struggled with the second part. I'm not sure if I was trying to make it too difficult or what happened; even after reading through all of the notes multiple times, I couldn't figure out exactly what I was supposed to do to attain the acceleration. If the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 50 clips / unit of ramp slope, and if the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 20 cm/s2) / clip, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If we require 45 clips to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?-- If the slope of the number of paperclips is 20cm/s^2, that means that for every paperclip added, the acceleration change of 20cm/s^2. If it takes 50 paper clips to equal 1 unit of ramp slope, then 20cm/s^2 * 50 = 1000 cm/s^2 change in acceleration per unit of ramp slope.