PHY121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Force on the 5kg will be 5kg*9.8m/s^2 = 49N. Force on the 6kg will be 6*9.8m/s^2 = 58.8N. I pick the 5kg's force to be negative. So the total force is 58.8N - 49N = 9.8N. Total mass of the system is 11kg, so acceleration = 9.8N/11kg = .9m/s^2.
v0= 1.8m/s. If the force is applied to the 5kg weight then the net force becomes 49N - 58.8N = -9.8N. a = -9.8N/11kg = -0.9 m/s^2. -0.9m/s^2 = `dv/`dt = `dv/1s = -.09(1) = `dv = -0.9. -0.9 = vf-1.8m/s = 0.9vf. The direction has changed.
The velocity is positive while the acceleration is negative, so they are opposite. The system speeds up.
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10 minutes
This appears to be OK but I can't tell for sure without seeing the problem.
Please resubmit this and include the statement of the problem.