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course Phy 121

10/26 630After reviewing your comments for what I should focus my time on I have marked problems I am comfortable with OK. Thank you

ce rating:3

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Question: `q013. On a graph of velocity v vs. clock time t we have the two points (5 s,

10 m/s) and (10 s, 20 m/s). What is the average slope of the graph between these

points, and what does this average slope mean?

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Your solution:

Slope=rise/run

(20 - 10m/s) / (10 - 5s) = (10m/s) / 5s = 2m/s^2

This slope shows the aAve is 2m/s^s

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