Phy 231
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
• Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion:
• Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward? It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion:
Answer: The component of the force is backward. This component is opposite to the direction of motion.
• Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion:
Answer: The object will slow down, the object will be moving in the horizontal direction at the same speed but will slow down in the vertical direction.
• If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left. Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion:
Answer: The line perpendicular to the direction of motion will run to your right.
• Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion:
Answer: The object would veer to the right because the line of motion veers of to the left.
• Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion:
Answer: The component perpendicular to the line of motion is greater in magnitude.
If you are facing in the direction of motion at 120 deg, then to get to the 270 deg direction you would have to turn 150 deg to your left, or 210 deg to your right. If you rotate slowly to the left you will reach the 150 deg position before you reach the 'backward' direction. So during this rotation you are always facing somewhat to the left of your original direction.
Thus the force vector has a component to the left, not to the right.
As a result the object will veer to the left.
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25 minutes
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&#Good work. See my notes and let me know if you have questions. &#