course Phy 231 m]Ӓῴg}assignment #000
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08:44:01 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> This query is completed to see if you understand the first assignments lab and homework. The professor can answer any qauestions about the material I might have.
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08:45:21 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> You divide distance by time. average speed = distance/time confidence assessment: 3
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08:49:05 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> average velocity = 40cm/5sec = 8 cm/sec For my object rolling down an incline experiment, I used very similar data. I used 290mm/1.9sec. average speed = 153mm/sec confidence assessment: 3
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08:51:06 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> It took 3 seconds to reach halfway, ave speed 1st half: 20cm/3sec = 6.7cm/sec ave speed 2nd half: 20cm/2sec = 10cm/sec confidence assessment: 3
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߀⪺DXbű assignment #000 000. `Query 0 Physics I 09-14-2008 vThf~EY assignment #000 000. `Query 0 Physics I 09-14-2008
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11:59:35 The Query program normally asks you questions about assigned problems and class notes, in question-answer-self-critique format. Since Assignments 0 and 1 consist mostly of lab-related activities, most of the questions on these queries will be related to your labs and will be in open-ended in form, without given solutions, and will not require self-critique. The purpose of this Query is to gauge your understanding of some basic ideas about motion and timing, and some procedures to be used throughout the course in analyzing our observations. Answer these questions to the best of your ability. If you encounter difficulties, the instructor's response to this first Query will be designed to help you clarify anything you don't understand. {}{}Respond by stating the purpose of this first Query, as you currently understand it.
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RESPONSE --> completed
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11:59:43 If, as in the object-down-an-incline experiment, you know the distance an object rolls down an incline and the time required, explain how you will use this information to find the object 's average speed on the incline.
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RESPONSE --> completed confidence assessment: 3
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11:59:54 If an object travels 40 centimeters down an incline in 5 seconds then what is its average velocity on the incline? Explain how your answer is connected to your experience.
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RESPONSE --> completed confidence assessment: 3
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12:00:04 If the same object requires 3 second to reach the halfway point, what is its average velocity on the first half of the incline and what is its average velocity on the second half?
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RESPONSE --> completed confidence assessment: 3
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14:24:33 Using the same type of setup you used for the first object-down-an-incline lab, if the computer timer indicates that on five trials the times of an object down an incline are 2.42 sec, 2.56 sec, 2.38 sec, 2.47 sec and 2.31 sec, then to what extent do you think the discrepancies could be explained by each of thefollowing: {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioningthe object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a) I believe the TIMER program is very accurate. The times are only to the nearest hundreth so I don't believe the TIMER program had anything to do with the discrepencies in time trials. b) There is probaly some discrepencies in the times due to the human clicking the mouse but very little. c) There might be a little difference in times because of the actual time required for the object to travel the distance but not much because, it's inside(i think) so there's no wind. And also if you use the same ramp, same book to elevate the ramp and the same surface under the book, there shouldn't be that big of a difference between runs. d) There could be big discrepencies because of positioning the object. For example if you are holding it with your finger, you might actually push the object up slightly when you take away your finger. e) There could also be big discrepencies because of uncertaintity when the object has reached the end of the incline. confidence assessment: 3
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14:25:55 How much uncertainty do you think each of the following would actually contribute to the uncertainty in timing a number of trials for the object-down-an-incline lab? {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated bLine$(lineCount) =with an actual human finger on a computer mouse){}{}c. Actual differences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> I don't see the difference from the last question. confidence assessment: 3
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14:31:27 What, if anything, could you do about the uncertainty due to each of the following? Address each specifically. {}{}a. The lack of precision of the TIMER program{}{}b. The uncertain precision of human triggering (uncertainty associated with an actual human finger on a computer mouse){}{}c. Actualdifferences in the time required for the object to travel the same distance.{}{}d. Differences in positioning the object prior to release.{}{}e. Human uncertainty in observing exactly when the object reached the end of the incline.
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RESPONSE --> a) You can't do anything about making the TIMER program more accurate. b) You can't do much about precision of human triggering. c) You could make sure to use the exact same materials on each run and make sure there is no wind at time of the trial to get rid of the actual differences in the time it takes the object to roll down the incline. d) To make sure you are releasing the object at the correct position each time, use a stick or something to hold the object at the top of the ramp and then release it by lifting the stick. Almost like a toll booth. This would make sure you release at the same time and don't push the object up or down the ramp. e) You can't really do much about this but I put my face very close to the end so that I could see when the object finished the ramp a little easier. confidence assessment: 3
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14:55:50 According to the results of your introductory pendulum experiment, do you think doubling the length of the pendulum will result in half the frequency (frequency can be thought of as the number of cycles per minute), more than half or less than half?
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RESPONSE --> From my results, doubling the length of the pendulum will result in more than half the frequency. confidence assessment: 3
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14:59:06 Note that for a graph of y vs. x, a point on the x axis has y coordinate zero and a point on the y axis has x coordinate zero. In your own words explain why this is so.
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RESPONSE --> For when x=0, the point has not traveled in the y direction. For when y=0, the point has not traveled in the x direction. confidence assessment: 3
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15:06:32 On a graph of frequency vs. pendulum length (where frequency is on the vertical axis and length on the horizontal), what would it mean for the graph to intersect the vertical axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the vertical axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> If it intersected the vertical axis the graph would indicate that at that point the length is equal to zero. confidence assessment: 3
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15:11:25 On a graph of frequency vs. pendulum length, what would it mean for the graph to intersect the horizontal axis (i.e., what would it mean, in terms of the pendulum and its behavior, if the line or curve representing frequency vs. length goes through the horizontal axis)? What would this tell you about the length and frequency of the pendulum?
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RESPONSE --> If the line intersected the horizontal axis, then at that point the frequency of the pendulum is equal to zero. confidence assessment: 3
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15:12:28 If a ball rolls down between two points with an average velocity of 6 cm / sec, and if it takes 5 sec between the points, then how far apart are the points?
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RESPONSE --> 6cm/sec * 5sec = 30cm confidence assessment: 3
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15:13:16 On the average the ball moves 6 centimeters every second, so in 5 seconds it will move 30 cm. {}{}The formal calculation goes like this: {}{}We know that vAve = `ds / `dt, where vAve is ave velocity, `ds is displacement and `dt is the time interval. {}It follows by algebraic rearrangement that `ds = vAve * `dt.{}We are told that vAve = 6 cm / sec and `dt = 5 sec. It therefore follows that{}{}`ds = 6 cm / sec * 5 sec = 30 (cm / sec) * sec = 30 cm.{}{}The details of the algebraic rearrangement are asfollows:{}{}vAve = `ds / `dt. We multiply both sides of the equation by `dt:{}vAve * `dt = `ds / `dt * `dt. We simplify to obtain{}vAve * `dt = `ds, which we then write as{}`ds = vAve *`dt.{}{}Be sure to address anything you do not fully understand in your self-critique.
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RESPONSE --> OK self critique assessment: 3
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15:23:09 You were asked to read the text and some of the problems at the end of the section. Tell me about something in the text you understood up to a point but didn't understand fully. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I don't understand question 19, on estimates and orders of magnitude. The question states there is a box of typewriter paper of dimensions 11in x 17in x 9in. The box says 10M and I'm supposed to find out if that means it's holing 10,000 sheets or 10 miliion sheets. I know the problem is looking for just an estimate but I don't know how to approximate how many papers are in the box. My guess is that the box holds 10,000 sheets but that I can't back that up with any math. confidence assessment: 0
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15:23:45 Tell me about something in the problems you understand up to a point but don't fully understand. Explain what you did understand, and ask the best question you can about what you didn't understand.
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RESPONSE --> I understood everything else. confidence assessment: 3
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