course Phy 231 ?????Z???????[??assignment #001001.
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21:52:45 Explain in your own words how the standard deviation of a set of numbers is calculuated.
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RESPONSE --> First you find the mean of the data points. Then you find the deviation for each data point from the mean. You then absolute value each number. Then square each deviation. Average the squared deviations then take the square root, and that is the standard deviation. confidence assessment: 3
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21:57:10 Explain in your own words the process of fitting a straight line to a graph of y vs. x data, and briefly discuss the nature of the uncertainties encountered in the process. For example, you might address the question of how two different people, given the same graph, might obtain different results for the slope and the vertical intercept.
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RESPONSE --> To approximate a best fit line between data points, Draw a line which you believe has an even average distance between the points. Some points will be closer to the line than others, but that's okay. This is just an approximation so two people can draw different lines if they think the average distance from the points is different. This will give different y intercepts, slopes, and different eqns. confidence assessment: 3
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21:59:12 Briefly state what you think velocity is and how you think it is an example of a rate.
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RESPONSE --> Velocity is the rate of change of speed. Rate is how fast something is moving and velocity is the rate at which someone is changing speeds. confidence assessment: 3
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22:01:15 ** A rate is a change in something divided by a change in something else. This question concerns velocity, which is the rate of change of position: change in position divided by change in clock time. **
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RESPONSE --> Velocity is the rate at which something is changing position. self critique assessment: 3
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22:03:54 Given average speed and time interval how do you find distance moved?
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RESPONSE --> distance moved = average speed * time interval confidence assessment: 3
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22:04:02 ** You multiply average speed * time interval to find distance moved. For example, 50 miles / hour * 3 hours = 150 miles. **
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RESPONSE --> OK self critique assessment: 3
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22:04:41 Given average speed and distance moved how do you find the corresponding time interval?
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RESPONSE --> clock time = distance moved/average speed confidence assessment: 3
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22:04:51 ** time interval = distance / average speed. For example if we travel 100 miles at 50 mph it takes 2 hours--we divide the distance by the speed. In symbols, if `ds = vAve * `dt then `dt = `ds/vAve. Also note that (cm/s ) / s = cm/s^2, not sec, whereas cm / (cm/s) = cm * s / cm = s, as appropriate in a calculation of `dt. **
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RESPONSE --> OK self critique assessment: 3
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22:05:39 Given time interval and distance moved how do you get average speed?
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RESPONSE --> average speed = distance moved/time interval confidence assessment: 3
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22:05:51 ** Average speed = distance / change in clock time. This is the definition of average speed. For example if we travel 300 miles in 5 hours we have been traveling at an average speed of 300 miles / 5 hours = 60 miles / hour. **
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RESPONSE --> OK self critique assessment: 3