course Phy 231
This is a resubmission of an assignment.
cq_1_72Phy 231
Your 'cq_1_7.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
?At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion:
Answer: ave vel1 = 10m/8sec = 1.25m/sec, vf = 2.5m/sec, dv = 2.5m/s, acceleration1 = 2.5m/s / 8s = .31m/s/s. ave vel2 = 10m/5s = 2m/s, vf = 4m/s, dv = 4m/s, acceleration2 = 4m/s / 5 s = .8m/s/s.
Your accelerations are calculated correctly.
ave acceleration of both runs = (.31m/s/s + .8m/s/s)/(2) = .6m/s/s.
Average slope = (.10 + .05)/2 = .08. Average rate of the automobile's acceleration changing with respect to the slope of the incline is .6m/s/s / .08 = 7.5.m/s/s.
&&&&.&# the average rate of change of A with respect to B=(A2-A1)/(B2-B1) = (.8m/s/s-.31m/s/s)/(.10-.05) = 9.8m/s/s. I hope this is right.
This is correct.
Dividing the average of your accelerations by the average of your ramp slopes does not give the average rate of change of acceleration with respect to ramp slope.
What is the definition of the average rate of change of A with respect to B?
How does this definition applied to the question asked here?
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15 minutes
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You did not calculate the final result correctly, though your accelerations are done correctly.
&#Please see my notes and submit a copy of this document with revisions and/or questions, and mark your insertions with &&&&. &#
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Good work. Let me know if you have questions.