course Phy 231 A ball reaches a ramp of length 68 cm with velocity of 19 cm/s. It accelerates uniformly along entire length of the ramp in 4.4 seconds. What is its acceleration?Answer: ds=(v0*dt) + (.5a*dt^2), .5adt^2 = ds – v0*dt, .5a = ds/dt^2 – v0/dt, a = 2ds/dt^2 – 2v0dt = 2(68cm)/(19.36s^2) – 2(19cm/s)/(4.4s) = 7cm/s/s – 8.6cm/s/s = -1.6cm/s/s